So this is p1 over t1 = p2 over t2. So you do 880/250=x/303 and then cross multiply and divide
Answer:
P2 = 19.2atm
Explanation:
Initial pressure (P1) = 16atm
Initial temperature (T1) = 340K
Final temperature (T2) = 408K
Final pressure (P2) = ?
This question involves the use of pressure law
Pressure law states that the pressure of a fixed mass of gas is directly proportional to it's temperature provided that volume is kept constant.
Mathematically,
P = kT, k = P / T
Therefore,
P1 / T1 = P2 / T2 = P3 / T3 = ......=Pn / Tn
P1 / T1 = P2 / T2
We need to solve for P2
P2 = (P1 × T2) / T1
Now we can plug in the values and solve for P2
P2 = (16 × 408) / 340
P2 = 6528 / 340
P2 = 19.2atm
The final pressure (P2) of the gas is 19.2atm
Answer:- partial pressure of Kr = 0.306 atm, partial pressure of oxygen = 0.264 atm and partial pressure of carbon dioxide = 0.396 atm
Total pressure is 0.966 atm
Solution:- moles of Kr = 21.7 g x (1mol/83.8g) = 0.259 mol
moles of oxygen = 7.18 g x (1mol/32g) = 0.224 mol
moles of carbon dioxide = 14.8 g x (1mol/44g) = 0.336 mol
Volume of container = 23.1 L and the temperature is 59 + 273 = 332 K
From ideal gas law equation, P = nRT/V
partial pressure of Kr = (0.259 x 0.0821 x 332).23.1 = 0.306 atm
partial pressure of oxygen = (0.224 x 0.0821 x 332)/23.1 = 0.264 atm
partial pressure of carbon dioxide = (0.336 x 0.0821 x 332)/23.1 = 0.396 atm
Total pressure of the gas mixture = 0.306 atm + 0.264 atm + 0.396 atm = 0.966 atm
