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3 years ago

An atom with a high metallic character usually has a electron affinity and a atomic radius.

Chemistry

1 answer:

lianna [129]3 years ago

8 0

Low electron affinity and large atomic radius

Metallic character decreases across a period (from left to right) and increases down a group.

Electron affinity increases from left to right within a period. This is caused by the decrease in atomic radius. Electron affinity decreases from top to bottom within a group. This is caused by the increase in atomic radius.

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An atom that normally has __________ electrons in its outer (valence) shell tends not to form chemical bonds with other atoms.

goblinko [34]

8 valence shell electrons.

5 0

3 years ago

My answer was 10 and it’s telling me it’s wrong..what did i do wrong?

Keith_Richards [23]

Answer:

1.586x10^-9

Explanation:

To make a multiplication in scientific notation we need to multiply the coefficients and sum the exponents:

Coefficients: 2.600 * 6.1000 = 15.86

Exponents: -5 + (-5) = -10

The result is:

15.86x10^-10

As the scientific notation must be given with only 1 number in the left of the point:

5 0

3 years ago

A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44

d1i1m1o1n [39]

Answer:

300.9mL

Explanation:

Given parameters:

V₁ = 280mL

T₁ = 22°C

T₂ = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

it is mathematically expressed as;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

We need to convert the temperature to kelvin;

T₁ = 22°C = 22 + 273 = 295K

T₂ = 44°C = 44 + 273 = 317K

Input the parameters and solve;

$\frac{280}{295}$ = $\frac{V_{2} }{317}$

V₂ x 295 = 280 x 317

V₂ = 300.9mL

5 0

3 years ago

The vapor pressure of ethanol at its normal boiling point would be

Galina-37 [17]

The normal boiling point<span> of </span>ethanol<span> is 78.4 degrees C and, at thistemperature, </span>the vapor pressure<span> is 101325 Pascals (Pa) or 760manometric units

thx hope this helped bye.</span>

4 0

3 years ago

9. If 28.56 g of K2O is produced when 25.00 g K is reactedaccording to the following equation, what is the percent yieldof the r

Mumz [18]

Answer

b. 95%

Explanation

Given:

Mass of K₂O produced (actual yield) = 28.56 g

Mass of K that reacted = 25.00 g

Equation: 4K(s) + O₂(g) → 2K₂0(s)

What to find:

The percent yield of K₂O.

Step-by-step solution:

The first step is to calculate the theoretical yield of K₂O produced.

From the balanced equation, 4 mol K produced 2 mol K₂O

Molar mass of K₂O = 94.20 g/mol)

Molar mass of K = 39.10 g/mol)

This means 4 mol x 39.10 g/mol = 156.40 g K produced 2 mol x 94.20 g/mol = 188.40 g K₂O

So 25.00 g K will produce:

$\frac{25.00\text{ }g\text{ }K\times188.40\text{ }g\text{ }K₂O}{156.40\text{ }g\text{ }K}=30.1151\text{ }g\text{ }K₂O$

Actual yield of K₂O = 28.56 g

Theoretical yield of k₂O = 30.1151 g

The percent yield for the reaction can now be calculated using the formula below:

$\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\ \\ Percent\text{ }yield=\frac{28.56\text{ }g}{30.1151\text{ }g}\times100\% \\ \\ Percent\text{ }yield=0.9484\times100\% \\ \\ Percent\text{ }yield=94.84\%\approx95\% \end{gathered}$

Therefore, the percent yield for the reaction is 95%.

3 0

1 year ago

An atom with a high metallic character usually has a ____ electron affinity and a ____ atomic radius.

An atom with a high metallic character usually has a electron affinity and a atomic radius.