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Anastaziya [24]
3 years ago
14

Describe the properties of noble gases. Based on their electronic arrangement, explain whether they can exist alone in nature.

Chemistry
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

In nature the atoms of noble gases do not bond either with other gases or with each other. Helium exists as atoms of Helium not as diatomic molecules. Some of the larger noble gases can be made to form molecules. This does not normally happen in natural conditions.

Explanation:Noble gases are odorless, colorless, nonflammable, and monotonic gases that have low chemical reactivity. The full valence electron shells of these atoms make noble gases extremely stable and unlikely to form chemical bonds because they have little tendency to gain or lose electrons.

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Explain how there can be more heat energy in an iceburg than in a pot of boiling water
vlada-n [284]

Heat energy is the amount of heat there is in a substance. This may be cold heat or warm heat. Temperature is how hot or cold a substance is. So because there is a higher volume of heat in the iceberg, we say it has more heat energy.
3 0
3 years ago
What are the coefficients that will balance this skeleton equation? AlCl3 + NaOH → Al(OH)3 + NaCl
almond37 [142]

Answer:

The coefficients are 1, 3, 1, 3

Explanation:

The equation;

AlCl3 + NaOH → Al(OH)3 + NaCl

can be balanced by using the coefficients  1, 3, 1, 3, such that the balanced equation will be;

AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

Chemical equations needs to be balanced so as to follow the law of conservation of mass. This occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

3 0
4 years ago
How does molecular shake affect polarity?
PSYCHO15rus [73]

Answer:

I believe its A

Explanation:

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7 0
3 years ago
What term refers to the period of life from puberty to the end of the teenage years?
Daniel [21]
A - adolescence.
 
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7 0
4 years ago
Given a fixed amount of gas held at constant pressure, calculate the volume (in L) it would occupy if a 3.50 L sample were coole
Over [174]

Answer:

V₂ = 2.91 L

Explanation:

Given data:

Initial volume = 3.50 L

Initial temperature = 90.0°C (90+273 = 363 K)

Final temperature = 30.0 °C  ( 30 +273 = 303 K)

Final volume = ?

Solution:

V₁ = Initial volume

T₁  =  Initial temperature

V₂ = Final volume

T₂ = Final temperature

V₁/T₁  =  V₂/T₂

3.50 L / 363 K) =  V₂ / 303 K)

V₂ = 0.0096 L/K × 303 K

V₂ = 2.91 L

6 0
3 years ago
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