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barxatty [35]
2 years ago
12

Are whole numbers _______ a natural number? always, sometimes, or never.

Mathematics
2 answers:
olga_2 [115]2 years ago
6 0

Answer:

whole numbers are sometimes a natural number

Step-by-step explanation:

negative numbers are whole numbers but not natural

loris [4]2 years ago
5 0

Answer:

sometime

Step-by-step explanation:

a natural number is a positive number ranging from 1-infinity and a whole number is a full number without fractions or decimals but can also be negative. Hope this helps.

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Find the sum of the first 50 positive even integers.
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50*(2+100)/2
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2 years ago
Variable y varies directly with variable x, and y = 6 when x = 20.
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In a direct proportion, the equation can be set up as
y = kx
k = y/x
k = 6/20
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2 years ago
How do you get 3/5 of 20
saveliy_v [14]

Answer:

Multiply 20 by 3/5

Step-by-step explanation:

<em>"of" mean to multiply</em>

20 "of" 3/5 equal 12   OR  20 x 3/5 = 12

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3 years ago
No entiendo ayuda plsssss
natulia [17]

Answer:

23/24

Step-by-step explanation:

I hope it will help

5 0
2 years ago
We often deal with weighted​ means, in which different data values carry different weights in the calculation of the mean. For​
Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

A = 82.5*0.3 + 88.6*0.3 + 0.4x

A \geq 93.5

82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5

0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)

x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}

x \geq 105.425

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0
3 years ago
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