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KonstantinChe [14]
3 years ago
11

Need help pleaseOn all three

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

1. proportional relationship

2. constant of proportionality

3. unit rate.

I'm not exactly sure on these answers, so please double check them for me to make sure that they are correct.

Step-by-step explanation:


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Where is the function f(x)=3x^2-6x-45/x^2-5x discontinuous, and what types of discontinuities does it have?
Vedmedyk [2.9K]

Answer:

Below.

Step-by-step explanation:

f(x)=3x^2-6x-45/x^2-5x

= 3x^2-6x-45 / (x(x - 5))

The denominator is zero when x - 0 and x = 5.

So there will be a vertical asymptote  at x = 0 and a hole at x = 5.

If we do the division  we get f(x)  = 3  remainder 9x - 45

so there will also be a horizontal asymptote where x = 3.

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2 years ago
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T takes 46 minutes for 10 people to paint 3 walls.
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Answer:

69 mins

Step-by-step explanation:

46/10=4.6 mins per wall

46/4=11.5 mins per wall

11.5 x 6=69

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Find the perimeter of the parallelogram with these vertices. (4,7), (-3,1), (4,1), (-3,-5) Give an exact answer (not a decimal a
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Answer: 4,1 read carefully

Step-by-step explanation:

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3 years ago
Find the volume of the following cube
kirza4 [7]
Pretty sure it’s 25 but I could be wrong. It’s also rly blurry. Hope this helps
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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.
Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

AC^{2} + BC^{2} = AB^{2}

AC^{2} + AD^{2} = AB^{2}      (Given that AD = BC)

AC^{2} + AD^{2} = 3^{2}      (Given that AB=3)

AC^{2} + AD^{2} = 9 ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

AD^{2} + CD^{2} = AC^{2}

AD^{2}+(\sqrt{2})^2= AC^{2}

AD^{2}+2= AC^{2}

AD^{2}=AC^{2} -2 ...(ii)


Plug value (ii) into (i)

AC^{2} + AC^{2}-2 = 9

2AC^{2} -2=9

2AC^{2} =11

AC^{2} =\frac{11}{2}

AC=\sqrt{\frac{11}{2} }


Hence final answer is AC=\sqrt{\frac{11}{2} }

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