Cables are forming 3 right angled triangles the pole being the shared height of them;
(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);
a^2 + b^2 = c^2
12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;
1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45
Add them up = 84yd of cable needed
Answer:
X=47.68degree
Step-by-step explanation:
tanx=56/51
x=tan^(-1)(56/51)
=47.68
5x²y²+10x²-7y²-14
Factor 5x² and -7 from the expression to get:
5x²(y²+2)-7(y²+2)
Factor out y²+2 from the equation
(5x²-7)(y²+2)
To find 10per cent just divide by 10, the answer is 8
