Answer:
The length for the 97th percentile for a man's arm span is 74.96 inches.
Step-by-step explanation:
We have a normal distribution for men's arm span, with mean of 68 inches and standard deviation of 3.7 inches.
The 97th percentil represents the value for which 97% of the observations are below.
We can search for the 97th percentile for the standard normal distribution. This will give a value z=1.88.
Then, we can convert this z-score to our distribution:

W= 34, thats what the answer is.
Answer:
m > 2
Step-by-step explanation:
7m - 2 > 12
Add 2 to both sides
7m - 2 + 2 > 14
7m > 14
Divide both sides by 7
m > 2