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kkurt [141]
3 years ago
9

The population of a nearby town dropped from 7,500 to 6,000 in one year.

Mathematics
1 answer:
jekas [21]3 years ago
5 0

Answer:5,600 - 3,500 = 2,100

2,100 is what percent of 3,500?

2,100 = X*3,500

X =  2,100 / 3,500

X = .60 or 60%

An average of 15% increase per year.

Step-by-step explanation:

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(9x-9)(9×+9), your finding the difference between two squares. im have some trouble in how to solve it.​
sergejj [24]

Answer: Your answer is 0 (F.O.I.L) first. outer. inner. last. Or you could use what my teacher calls the magic box

Step-by-step explanation:

So for the boxes you multiply for example the top left box you multiply the 9 above it and the 9 to the left or like the top right box you multiply the -9 above it and the 9 on the outside of the box to the left

8 0
3 years ago
Can someone help? It’s about 2 column proofs
Gwar [14]

Step-by-step explanation:

1. AB = BC (B is the midpoint of AC)

2. DE = EF (E is the midpoint of DF)

3. EB is common

4. ∠ABE = ∠CBE; ∠BED = ∠BEF (EB⊥AC, EB⊥DF)

5. ΔDEB ≅ ΔFEB (RHS)

6. DB = FB (corresponding ∠s of ≅ Δs)

7. ∠EFB = ∠CBF; ∠EDB = ∠ABD (alternate interior angles, AC║DF)

8. ΔABD ≅ ΔCBF (SAS)

4 0
3 years ago
Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.
VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let \mu = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, H_0 : \mu \geq 30 minutes      {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, H_A : \mu < 30 minutes     {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean commute time = 27.6 minutes

            s = sample standard deviation = 19.6 minutes

            n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u>  =  \frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }  ~ t_4_9_9

                                       =  -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0
4 years ago
F = 1.8 C + 32<br> (a) Work out the value of F when C = -8
dybincka [34]

Answer:

17.6°

Step-by-step explanation:

1.8x-8=-14.4

-14.4 + 32= 17.6°C

5 0
3 years ago
Find the greatest common factor: 4ab^2 c^4-2a^2 b^3 c^2+6a^3 b^4 c
Tatiana [17]
Well the GCF is the number that can be used to simplify, or that fits in all of your numbers for example this are all small numbers so 2 should fit in all of them 2 fits in 4 two times 2 fits in 2 one time and 2 fits in 6 three times now lets check our variable, to find the GCF of the variable first chekc if they all have the same if they don't u can't get none of taht variebles out, but if they repeat in all like the a u will take out the smallest amount out, for example the a as one in the degree of 1 the other in to the 2 degree and the last one to teh 3 degree well the smallest degree will be 1 so u will only take 1 a out so now ur GCF looks like 2a... Lets check the other variables, b is used in all of them and the smallest degree is b2 so we will take out 2 b's out so now my GCF looks like 2ab2 now lets check our last variable the, the c has the smallest degree of 1 so we will only take 1 c out
this means our final GCF is "2ab2c"

Hoep this helps
6 0
3 years ago
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