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ozzi
3 years ago
6

Perform the following operations on the vectors u=⟨1,3⟩ and v=⟨−3,4⟩

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0

Answer:

las;kdfj;la sdjfla sjdfl;asdl;f ajd;fasjdlf ;asdlkjf ;lasjd f;las dflka sf;lk asdjf as i omg i am so msart

Step-by-step explanation:

You might be interested in
Helpppplpppp<br><br><br><br><br> Which choice is equivalent to the product below?
Maurinko [17]

Answer:

6

Step-by-step explanation:

=>root(2) x root(3) x root(6)

=>root(2x3) x root(6)

=>root(6) x root(6)

=>6

3 0
3 years ago
22.a) A fruit vendor bought 1948 oranges on a Thursday and sold 750 of them on the same day.
iVinArrow [24]

Answer: Ksh 6144

Step-by-step explanation:

On Thursday, a fruit vendor bought 1948 oranges on a Thursday and sold 750. The number of oranges left will be: = 1948 - 750 = 1198

On n Friday, he sold 240 more oranges than on Thursday. This means the number of oranges sold is: = 240 + 750 = 990.

The number for f oranges left will then be: = 1198 - 990 = 208

On Saturday, he bought 560 more

oranges, the total oranges that the vendor has now will be:

= 208 + 560 = 768

Since sold all the oranges he had at a price of Ksh. 8 each, the amount if money made will be:

= Ksh 8 × 768

= Ksh 6144

The vendor made Ksh 6144

7 0
3 years ago
Please help me!!
nikitadnepr [17]

its the first one

Step-by-step explanation:

because per pertains to to x

8 0
3 years ago
Hi, can somoene please check why my solution and explain why I get the wrong answer.
trapecia [35]

Answer:

a_n=(1-n)2^n+3^n

Step-by-step explanation:

You are correct down to the part where you add the partial results:

a_n=a_n^h+a_n^p=A3^n+B2^n-n2^n\\\text{Using the given starter values, we can find A, B:}\\a_0=2=A\\a_1=7=3A+2B+2\\\text{has solution A=1, B=1, so ...}\\\\a_n=3^n+2^n-n2^n

4 0
3 years ago
Does someone know the answer? Simplify it <br> 3(2a^2-3a+1)-(2a+7)
igor_vitrenko [27]

Answer:

5a3-5a2

Step-by-step explanation:

7 0
3 years ago
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