System A has ONE real solution
System B has NO real solutions
System C has ONE real solution
Answer: 33/3
Step-by-step explanation:
I don't know the question is weird but it probably is 33/3
Divide 560 by 23, 23 goes into 560 24.347 times.
Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:

⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
Triangle A:
y = 57.5°
x = 57.5°
Triangle B:
y = 5
x = 6.5
Triangle C:
... I apologize but I do not know what Triangle C is. Sorry!!
Triangle D:
z = 30°
x = 90°
(x+20) = 110°
SORRY THAT TOOK SO LONG--