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matrenka [14]
3 years ago
6

You have to make it balanced.

Physics
1 answer:
Harman [31]3 years ago
8 0

2NCl3--- N2 + 3Cl2

hope it helps

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A 0.2 kg block sliding on a horizontal table slows down from 25 m/s to 20 m/s. How much energy does the block lose due to fricti
Papessa [141]

Answer:

the kinetic energy lost due to friction is 22.5 J

Explanation:

Given;

mass of the block, m = 0.2 kg

initial velocity of the block, u = 25 m/s

final velocity of the block, v = 20 m/s

The kinetic energy lost due to friction is calculated as;

\Delta K.E= K.E_f - K.E_i\\\\\Delta K.E= \frac{1}{2}mv^2 -  \frac{1}{2}mu^2\\\\\Delta K.E= \frac{1}{2}m(v^2 -u^2)\\\\\Delta K.E= \frac{1}{2} \times 0.2 (20^2 - 25^2)\\\\\Delta K.E= -22.5 \ J

Therefore, the kinetic energy lost due to friction is 22.5 J

7 0
3 years ago
Read 2 more answers
A 4m^3 container is being filled at a rate of 0.051m^3/s. What is the time required to completely fill this container?
Anna007 [38]

Answer:

Time required to completely fill this container = 78.43 seconds

Explanation:

Volume of container = 4 m³

Rate of filling of container = 0.051 m³/s

We have the equation

             \texttt{Time required}=\frac{\texttt{Volume of container}}{\texttt{Rate of filling of container}}

Substituting

             \texttt{Time required}=\frac{4}{0.051}=\frac{4000}{51}=78.43 s

Time required to completely fill this container = 78.43 seconds

3 0
4 years ago
Material through which a mechanical wave moves?
polet [3.4K]

Answer:

Medium

Explanation:

A mechanical wave moves through any medium, meaning any physical matter. A medium can be any state of matter, such as a liquid, gas or solid. An example of a mechanical wave is sound, which is the vibration of matter.

4 0
3 years ago
Plz help! Which of the following statements is tru about the villi.
ANTONII [103]
It is the primary site for nutrient absorption into the blood stream after being digested into small molecules with enzymes.
7 0
4 years ago
A 1.83 kg1.83 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.52
almond37 [142]

Answer:

9.4 N

Explanation:

m = mass of the book = 1.83 kg

\mu _{s} = Coefficient of static friction = 0.522

\mu _{k} = Coefficient of kinetic friction = 0.283

f_{s} = Static frictional force

F = force needed to make the book move

force needed to make the book move is same as the magnitude of maximum static frictional force applied by the desk on the book

Static frictional force is given as

f_{s} = \mu _{s} mg

Hence, the force need to move the book is given as

F = f_{s} = \mu _{s} mg

F = \mu _{s} mg

F = (0.522) (1.83 x 9.8)

F = 9.4 N

4 0
3 years ago
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