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wolverine [178]
3 years ago
8

Two sources of light of wavelength 720 nm are 10 m away from a pinhole of diameter 1.2 mm. How far apart must the sources be for

their diffraction patterns to be resolved by Rayleigh's criterion?
Physics
1 answer:
julia-pushkina [17]3 years ago
6 0

Answer:

The value is  y  =  0.00732 \ m    

Explanation:

From the question we are told that

    The wavelength of each source is  \lambda  = 720 \ nm =  720 *10^{-9} \  m

     The distance from the pinhole D = 10 \ m

     The diameter is d =  1.2 mm = \frac{1.2}{1000} = 0.0012 \ m

Generally from Rayleigh's criterion  we have that the distance between the sources of light for their diffraction patterns is mathematically represented as '

        y  =  \frac{ 1.22 *  \lambda *  D}{d}

=>      y  =  \frac{ 1.22 * 720 *10^{-9}*   10 }{ 0.0012}

=>      y  =  0.00732 \ m      

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Answer:

Explanation:

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3 years ago
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Answer:

Explanation:

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the position x where half of the original spring potential exists is found where

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The distance the object willl fall durring the 2nd seconds is 4.9 m

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

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