A 4m^3 container is being filled at a rate of 0.051m^3/s. What is the time required to completely fill this container?
1 answer:
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You need the kinematic equation for distance as a function of acceleration:
![d = [v(initial) *t] + 0.5a*t^{2}](https://tex.z-dn.net/?f=d%20%3D%20%5Bv%28initial%29%20%2At%5D%20%2B%200.5a%2At%5E%7B2%7D)
where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
t = time of fall
if the stone started at rest then v(initial) = 0 making the equation simply
Let me know if you still need further help :)
where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
t = time of fall
if the stone started at rest then v(initial) = 0 making the equation simply
Let me know if you still need further help :)