Question

A 4m^3 container is being filled at a rate of 0.051m^3/s. What is the time required to completely fill this container?

Answer 1

Answer:

Time required to completely fill this container = 78.43 seconds

Explanation:

Volume of container = 4 m³

Rate of filling of container = 0.051 m³/s

We have the equation

             $\texttt{Time required}=\frac{\texttt{Volume of container}}{\texttt{Rate of filling of container}}$

Substituting

             $\texttt{Time required}=\frac{4}{0.051}=\frac{4000}{51}=78.43 s$

Time required to completely fill this container = 78.43 seconds