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taurus [48]
4 years ago
11

TanA+tanB=sin(A+B)/cosAcosB

Mathematics
1 answer:
Elden [556K]4 years ago
4 0
Do you need to prove that it is equal?
If so:

SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB

(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB

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