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taurus [48]
4 years ago
11

TanA+tanB=sin(A+B)/cosAcosB

Mathematics
1 answer:
Elden [556K]4 years ago
4 0
Do you need to prove that it is equal?
If so:

SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB

(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB

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3 years ago
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I REALLY NEED HELP ASAP
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Please explain the steps on how to solve it! (Answer is selected)
LenKa [72]

Answer:

5x - 2y = -10 (B.) This should be right so if its not let me know I am stumped on what else it would be

Step-by-step explanation:

Parallelism: Same slope but different y-intercept

1 - Get into slope formula

 5x - 2y = 7

<u>- 5x           -5x                </u>

       -2y = -5x + 7

  -2y/-2 = -5x/-2 +7/-2

    y = (5/2)x - 7/2

2 - Plug x and y from (0, 5) into y = mx + b however note the - 7/2 is extranneous and wont be used for b

    y = (5/2)x + b

   5 = (5/2)0 + b

   5 = 0 + b

   5 = b

Therefore

y = 5/2x + 5 is your slope formula.

Now to get x to the other side.

3 - Get it back to standard form.

        y = 5/2x + 5

- 5/2x    -5/2x

- 5/2x + y = 5

(Multiply 2 into everything to get rid of the fraction)

   -5x + 2y = 10

3 0
3 years ago
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Answer:

g=31/69

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I'm pretty sure the answer would be 30 people.
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