4 years ago

TanA+tanB=sin(A+B)/cosAcosB

1 answer:

4 0

Do you need to prove that it is equal?
If so:

SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB

(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB

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What is the sum of (2+4i) and (7+11i)

Romashka [77]

Add like terms
2+4i +7 +11 i =
2+7 + 4i+11i =
9+15i

3 0

4 years ago

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F(x)=−2x+16<br> g(x)=4x+10<br> please give me the intersection points

vagabundo [1.1K]

Answer:

(1, 14)

Step-by-step explanation:

The intersection is when both functions have same coordinates

f(x) = g(x)

Substitute to get

- 2x + 16 = 4x + 10
4x + 2x = 16 - 10
6x = 6
x = 1

The y- coordinate is

y = - 2(1) + 16 = -2 + 16 = 14

So the intersection point is (1, 14)

7 0

3 years ago

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Maria needs two pieces of wire for a project.The first piece is 5.2cm long.the second piece must be 1.5 times as long. how long

Reptile [31]

First piece is 5.2 cm...and second piece is 1.5 times as long
1.5(5.2) = 7.8 cm <== second piece

7 0

4 years ago

What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in

xeze [42]

ANSWER

$197 {in}^{2}$

EXPLANATION

The area of the two tra-pezoidal faces

$= 2 \times \frac{1}{2} \times (9 + 5) \times 5 = 70 {in}^{2}$

The area of the 5 by 6.4 rectangular face

$= 6.4 \times 5 = 32 {in}^{2}$

The area of the two square faces

$= 2(5 \times 5) = 50 {in}^{2}$

The area of the 9 by 5 rectangular face is

$= 9 \times 5 = 45 {in}^{2}$

The surface area of the design is:

$70 + 32 + 50 + 45=197 {in}^{2}$

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3 years ago

What is the difference between volume and surface area?

TiliK225 [7]

Volume is the amount of inner space of a 3d object. surface area is the area of the outer surface

3 0

3 years ago

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