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Varvara68 [4.7K]
3 years ago
6

The Periodic table below shows major regions in different colors. In this periodic table, which type of element is shown in gree

n boxes?

Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The Correct choice is~ B

The elements shown in green boxes are ~ <u>Metalloids</u>

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Assuming your weight is 440.55 N and the force of gravity on Earth is 9.8 m/s2 what is your mass? *
Alexandra [31]

Answer:

44.95408163 kg

44.95 kg (2 decimal places)

Explanation:

Weight=Mass*Gravity

440.55=m*9.8

Make m the subject

M=440.55/9.8

M= 44.95 kg

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4 years ago
Calculate the weight percent of ascorbic acid in a tablet of Vitamin C from the following data:A 80 mg sample of a crushed Vitam
Lina20 [59]

Answer:

The Answer is 88%

Explanation:

The balanced ionic equation of the reaction

   IO^{3- }+ 8 I^- + 6 H^+ => 3 I^{3- }+ 3 H_2O

  I^{3-} + 2 S_2O_3^{2-} => 3 I^- + S_4O_6^{2-}

 

  C_6H_8O_6 + I^{3- }+ H_2O => C_6H_6O_6 + 3 I^- + 2 H^+

Looking at the above reactions

   The original number of moles of I^{3-} = 3 × number of moles of IO^{3-}

                                                                = 3 × volume × concentration of KIO_3

Note: The formula for number of moles is volume × concentration

                                                                =3 * \frac{40}{1000} *  0.00653 =0.000784 mol

The number of moles of I^{3-} left after its reaction with ascorbic  acid

                         = \frac{1}{2} x moles of S_2O_3^{2-}

                          = \frac{1}{2} x volume x concentration of    S_2O_3^{2-}

                          = \frac{1}{2}  * \frac{15}{1000} * 0.0510 =0.000383 \ mol

Note: The division by 1000 is to convert mill liter to liter

                             Moles of ascorbic acid = moles of I^{3-} reacted

                           = initial \ moles \ of \  I^{3-} \ - remaining \ moles \ of \ I^{3-}

                           =0.000784 - 0.000383

                          =0.000401 \ mols

              Mass =  moles \ * molar \ mass

Hence

              Mass of ascorbic acid = moles of ascorbic acid × molar mass of ascorbic acid

                                                      = 0.000401* 176.12 = 0.07055\ g

                                                      = 70.55\  mg

 Weight% of ascorbic acid = mass of ascorbic acid/mass of sample x 100%

                                             = 70.55/80  × 100%

                                              = 88.1%

                       

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4 years ago
How many moles of oxygen atoms are on 4.7x1022 molecules of carbon dioxide?
scoundrel [369]

Answer:

0.076

Explanation:

n=4.7×10^22/6.022×10^23

n=0.076mol

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They do form directly on the equators
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Which statement best describes the role of the skeleton?
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Answer:

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