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Elenna [48]
2 years ago
8

What is (16x+9)+(−9x−5) ?

Mathematics
2 answers:
seropon [69]2 years ago
8 0

Answer:

7+4

Step-by-step explanation:

hope it helps

ZanzabumX [31]2 years ago
8 0
The awnswer is 11 hope it helps
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Find the equation in slope-intercept form (10,4) that is perpendicular to y=5x-3
TEA [102]
Perpendicular equation: y=-1/5x + 6
7 0
3 years ago
What is the percentage chance of a solution 150 g active ingredient in a total of 1000 mL of solution
Andrej [43]

Answer:6.6666666667

Step-by-step explanation:just divided it

4 0
3 years ago
-5x+35=40<br><br>what are the steps?​
Svetlanka [38]

Answer:

Step-by-step explanation:

-5x + 35 = 40

Subract 35 from both sides -5x + 35 - 35 = 40 - 35  = (-5x = 5)

Divide -5 from both sides -5x / -5 = 5 / -5 =

x = -1

7 0
2 years ago
Read 2 more answers
In our family there is five boys and one girl. What percent of the family is boys?
saw5 [17]

Answer:

83% are boys

Step-by-step explanation:

Im not sure if you have to round but you take the total number of family members (6) and divide it by how many boys (5) which would be 0.8333333 which you can round to either 80 or 83

8 0
3 years ago
If 2tanA=3tanB then prove that,<br>tan(A+B)= 5sin2B/5cos2B-1​
Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

tan(A + B) = (3/2 tan(B) + tan(B)) / (1 - 3/2 tan²(B))

… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

… = 10 sin(B) cos(B) / (4 (cos²(B) - sin²(B)) - 2 sin²(B))

… = 5 sin(2B) / (4 cos(2B) - 2 sin²(B))

The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

so it follows that

tan(A + B) = 5 sin(2B) / (4 cos(2B) + 1 - 2 sin²(B) - 1)

… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

5 0
2 years ago
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