Answer:
This is a geometric sequence and the ratio is equal to 4.
Step-by-step explanation:
Arithmetic means you can continue the sequence through addition or subtraction.
Geometric means you can continue the sequence through multiplication or division.
To get from 3 to 12, we could either add 9 (arithmetic) or multiply by 4 (geometric).
To get from 12 to 48, we could either add 36 or multiply by 4.
Since we are looking for a pattern, the sequence would be geometric. This is because the sequence can be continued by multiplying by 4 each time. It cannot be arithmetic because we cannot add by 9 each time.
On a side note, common difference is used when describing arithmetic while ratio is used to describe geometric.
Answer:
(t + 6)(t - 6)
Step-by-step explanation:
(t - 6)(t + 6)
(t . t) + (t . (6) + ((-6) . t) + ((-6) . 6)
= t² - 6t + 6t - 36
= t² - 36
so,
t² - 36 = (t + 6)(t - 6)
Answer:
6.2832 square units (rounded off to four decimal values)
Step-by-step explanation:
Area of a semicircle =
× π × r²
r (radius) = 2 units
For our semicircle the area =
× π × 2² = 6.28318530718 square units
Or 6.2832 square units (rounded off to four decimal values)
Answer:
1716 ;
700 ;
1715 ;
658 ;
1254 ;
792
Step-by-step explanation:
Given that :
Number of members (n) = 13
a. How many ways can a group of seven be chosen to work on a project?
13C7:
Recall :
nCr = n! ÷ (n-r)! r!
13C7 = 13! ÷ (13 - 7)!7!
= 13! ÷ 6! 7!
(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)
1235520 / 720
= 1716
b. Suppose seven team members are women and six are men.
Men = 6 ; women = 7
(i) How many groups of seven can be chosen that contain four women and three men?
(7C4) * (6C3)
Using calculator :
7C4 = 35
6C3 = 20
(35 * 20) = 700
(ii) How many groups of seven can be chosen that contain at least one man?
13C7 - 7C7
7C7 = only women
13C7 = 1716
7C7 = 1
1716 - 1 = 1715
(iii) How many groups of seven can be chosen that contain at most three women?
(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)
Using calculator :
(15 * 35) + (6 * 21) + (1 * 7)
525 + 126 + 7
= 658
c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?
(First in second out) + (second in first out) + (both out)
13 - 2 = 11
11C6 + 11C6 + 11C7
Using calculator :
462 + 462 + 330
= 1254
d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?
Number of ways with both in the group = 11C5
Number of ways with both out of the group = 11C7
11C5 + 11C7
462 + 330
= 792