So the equation would be “a squared +4 squared=8 squared.” Then you would square 4 which would be 16 and 8 which would be 64. Now the equation is a squared+ 16=64 the rest is basic algebra. Subtract 16 from 64 which is 48. Now you have a squared= 48. You get the square root of both sides so now you have the square root of a is 6.9. I’m pretty sure that’s how you do it. I apologize if I’m incorrect.

5 0

2 years ago

3. The equation 4x + 16y = 36 is a true equation for a particular

Kazeer [188]

Answer:

See below.

Step-by-step explanation:

We know that the equation $4x+16y=36$ is a true equation for a particular value of x.

Now, let's see what happens if we divide everything by 4. In other words:

$\frac{4x+16}{4}=\frac{36}{4}$

Divide:

$x+4=9$

So, we get $x+4=9$ .

When we divided everything by 4, we used the division property of equality. Under this property, the equation remains the same even if we divided since we did the <em>same thing to both sides of the equation. </em>

Therefore, $x+4y=9$ is also true for the same value of x because it is just a simplified version of $4x+16y=36$ .