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3 years ago

Of the 345 7th graders, 40% of them are in band. How many 7 graders are in band?

Mathematics

2 answers:

pav-90 [236]3 years ago

6 0

So first you find 10% which is 34.5

Then you multiply 10% by 4 to get 40% which is = 138s

xz_007 [3.2K]3 years ago

3 0

So first you find 10% which is 34.5
Then you multiply 10% by 4 to get 40% which is = 138

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USPshnik [31]

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2 years ago

Suppose that to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77, 71, 77, and 67 i

lord [1]

A score of 78

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3 years ago

Read 2 more answers

If he drank 80% of his water on his entire hike. How much did he drink? (Remember he brought 3 liters of water.)

Mama L [17]

Answer:

<h2>2.4 Litres of water</h2>

Step-by-step explanation:

80% of (3 litres)

You can take 3 litres to be 3000 ml which is how I solved it.

<h2>OPTION 1</h2><h2>_________</h2>

80/100 x 3000

=2400 or 2.4 litres

The same can go with not taking ml which you can just use litres

<h2>OPTION 2</h2><h2>_________</h2>

80/100 x 3

=2.4 litres

I used the ml since I do not need the calculator for that one and it is faster to calculate.

6 0

3 years ago

Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 h

stira [4]

Answer:

The percent of the parts are expected to fail before the 2100 hours is 0.15.

Step-by-step explanation:

Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.

To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.

Solution:

We will use z score formula

$z=\frac{x-\mu}{\sigma}$

Mean value = $\mu = 2500$

Standard deviation = $\sigma = 135$

We are supposed to find If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?

So we are supposed to find P(z<2100)

so, x = 2100

Substitute the values in the formula

$z=\frac{2100-2500}{135}$