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taurus [48]
3 years ago
12

‏Mr. Jones's prescription calls for 1.04 tablets per day. Based on this information, how many tablets should Mr. Jones take per

day? a) 1.25 O b) 1.5 c) 1 O d) 2
I think the answer is a but I'm not sure I'm really a little confused I want to check with this app please can someone heelp me
Physics
1 answer:
Papessa [141]3 years ago
3 0

Answer:

c

Explanation:

It really depends on what the stuff is. This should not be a math or physics question.

Having said that, I answer it by rounding it to 1.       1.04 is closest two one.

That is not entirely a satisfactory answer. Most people who take medications have pill splitters. They easily cut a pill in half. They can do this only if a the medicine's directions, or a pharmacist, or a doctor tells you can do this. Cutting it into quarters should never be done.

So a is really incorrect medically.

1.5 is too far away

C is probably the intended answer; it would annoy me no end if it was anything but c. If this was just a rounding question, it rounds to c. There is no medication that requires an intake of 1.04. No one could get that kind of accuracy.

2 is really too far away.

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what is the specific heat capacity of silver metal if 55.00g of the absored 47.3 calories of heat and temperature rise 15.°c​
igor_vitrenko [27]

Answer:

0.240 J/(g^{\circ}C)

Explanation:

When an amount of energy Q is supplied to a sample of substance of mass m, the temperature of the substance increases by \Delta T according to the equation

Q=mC_s \Delta T

where

C_s is the specific heat capacity of the substance

In this problem, we have:

m = 55.0 g is the mass of the sample of silver

Q = 47.3 \cdot 4.184 = 197.9 J is the amount of energy supplied to the sample

\Delta T = 15^{\circ}C is the change in temperature of the sample

Solving the equation for C_s, we find the specific heat capacity of silver:

C_s = \frac{Q}{m \Delta T}=\frac{197.9}{(55.0)(15)}=0.240 J/(g^{\circ}C)

3 0
4 years ago
Choose the best description of the attraction between you and your classmate.
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Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

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For an in between distance of 1 m and equal masses of 60 kg, we have;

F = G \times \dfrac{m_{1}  \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11}  \times \dfrac{60 \times 60}{1^{2}}  \approx  2.403 \times 10^{-7} N

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Answer:

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