Answer:
— 159.6°C
Explanation:
Data obtained from the question include:
V1 (initial volume) = 960L
T1 (initial temperature) = 38°C = 38 + 273 = 311K
V2 (final volume) = 350L
T2 (final temperature) =?
Since the pressure is constant, then Charles' law is in operation. Using the Charles' law equation V1/T1 = V2/T2, we can easily obtain the final temperature as follow:
V1/T1 = V2/T2
960/311 = 350/T2
Cross multiply to express in linear form.
960 x T2 = 311 x 350
Divide both side by 960
T2 = (311 x 350) /960
T2 = 113.4K
Now let us convert 113.4K to a number in celsius scale. This is illustrated below:
°C = K — 273
°C = 113.4 — 273
°C = — 159.6°C
Therefore, the container will have a volume of 350L at — 159.6°C
Answer:
pH is a measure of hydrogen ion concentration, a measure of the acidity or alkalinity of a solution. The pH scale usually ranges from 0 to 14. Aqueous solutions at 25°C with a pH less than 7 are acidic, while those with a pH greater than 7 are basic or alkaline. A pH level of 7.0 at 25°C is defined as "neutral" because the concentration of H3O+ equals the concentration of OH− in pure water. On the other hand, electrical conductivity is a non-specific measurement of the concentration of both positively and negatively charged ions within a sample. So the short answer to the question is as follows, the presence of any hydrogen ions present in a substance will impact the pH level and most probably influence conductivity levels. However, hydrogen ions make up only a small part of the ion concentration measured by a conductivity meter.
Answer:
True.
Explanation:
You didn't provide an answer, but I'm assuming this is a T/F question.
Answer:
126.99g
Explanation:
NiO has a molar mass of 74.7 g/mol. This means that one mole of nickel (II) oxide has a mass of 74.7 grams. We can use stoichiometry/dimensional analysis to figure out how many grams are in 1.7 moles.
Answer:
The limiting reactant is propene, 
.
Explanation:
Moles of nitrogen propene = 2 mol
Moles of oxygen = 10 mol
According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:
According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.
The limiting reactant is propene, hence the correct answer is the .
