A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:
<span>
Organic Compound + Oxygen = CO2 + H2O
</span><span>To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.
</span><span>
7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C
Therefore, 0.167 mol of C was originally in the sample.</span>
Answer:
Check the explanation
Explanation:
functional group found in the major organic product = alpha -beta unsaturated ketone
Reaction used to form this functional group = Michael condensation reaction
Also other reactions are - Aldol condensation , Robinson annulation reaction.
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Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
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Answer:
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Explanation:
