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3 years ago

Definition empirical evidence

Chemistry

2 answers:

borishaifa [10]3 years ago

4 0

Empirical evidence is information acquired by observation or experimentation.

Mkey [24]3 years ago

3 0

Answer:

Empirical evidence for a proposition is evidence, i.e. what supports or counters this proposition, that is constituted by or accessible to sense experience or experimental procedure. Empirical evidence is of central importance to the sciences and plays a role in various other fields, like epistemology and law

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how many grams of silver medal could be recovered from a reaction of 50 g silver nitrate and copper metal

Likurg_2 [28]

Answer:

Answer is: mass of copper is 127 grams.

Balanced chemical reaction: Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s).

m(Ag) = 432 g.

n(Ag) = m(Ag) ÷ M(Ag).

n(Ag) = 432 g ÷ 108 g/mol.

n(Ag) = 4 mol.

From chemical reaction: n(Ag) : n(Cu) = 2 : 1.

n(Cu) = 4 mol ÷ 2 = 2 mol.

m(Cu) = n(Cu) · M(Cu).

m(Cu) = 2 mol · 63.5 g/mol.

m(Cu) = 127 g

Explanation:

7 0

3 years ago

The question is below

nevsk [136]

The reducing agent is donating electrons and therefore becoming oxidised itself. In this scenario elemental zinc (Zn) is in a reduced state and is oxidised to become Zn2+, in doing so it donates electrons to Fe2+, thereby reducing it to elemental iron (Fe).

The elemental Zinc in solid state is therefore the reducing agent as it reduces Fe2+ to Fe(s).

7 0

3 years ago

What two atoms are held together by a covalent bond in NaHCO3

gtnhenbr [62]

Answer: covalent bond is the force of attraction that holds together two atoms that share a pair of valence electrons. Covalent bonds form only between atoms of nonmetals. The two atoms that are held together in a covalent bond may be atoms of the same element or different elements.

Explanation:

8 0

2 years ago

What is the molar mass of Sn(CO3)2?

Free_Kalibri [48]

Answer:

The molar mass and molecular weight of Sn(CO3)2 is 238.728.

Explanation:

7 0

2 years ago

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago