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Anvisha [2.4K]
2 years ago
6

Write and balance chemical reactions for the following reactions and name the reaction type:

Chemistry
1 answer:
trapecia [35]2 years ago
4 0

Answer: The reaction of 1 mol of C to form carbon monoxide in the reaction 2 C(s) + O2(g) ( 2 CO(g) releases 113 kJ of heat. How much heat will be released by the combustion of 100 g of C according the the above information? According to the balanced chemical equation;

Explanation:

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Structure of 4-ethylheptene
Kisachek [45]

Answer:

PubChem CID 16663

Structure Find Similar Structures

Chemical Safety Laboratory Chemical Safety Summary (LCSS) Datasheet

Molecular Formula C9H20

Synonyms 4-ETHYLHEPTANE 2216-32-2 Heptane, 4-ethyl- 4-ethyl-heptane 4-ethyl heptane

Explanation:

7 0
3 years ago
Which skeleton equation represents a neutralization reaction? Mg + O2 MgO AlCl3 Al + Cl2 Li + HNO3 H2 + LiNO3 HBr + LiOH LiBr +
creativ13 [48]
Neutralization reaction is the reaction between acid and base.
There the neutralization reaction is:

HBr + LiOH ----------> LiBr + H2O.

Hope this helps!
5 0
2 years ago
Read 2 more answers
Neon lamps, is composed of 90.483% of 20ne, 0.271% of 21ne, and 9.253% of 22ne. the 20ne atoms have a mass of 19.992 u, 21ne ato
WITCHER [35]

20.181 u

The average atomic mass of Ne is the <em>weighted average</em> of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,  

Avg. at. mass

= (0.904 83× 19.992 u) + (0.002 71 × 20.994) + (0.092 53× 21.991 u)

= 18.0894 u + 0.0569 u  + 2.0348 u = 20.181 u

8 0
3 years ago
How many Calories are there in 4600 Joules?
mars1129 [50]

Answer:

1099.426

Explanation:

4 0
3 years ago
Find the enthalpy change per mole of sodium when sodium reacts with water. 13 grams of sodium reacts with 247 cm3 of water, prod
Ierofanga [76]

The answer is

-79 kJ/mol

The explanation:

The reaction equation is:

2Na + 2H2O  2NaOH + H2

when ΔHrxn= -q

and q=cmΔT

where:

-q is amount of heat absorbed/released

-and c is specific heat of solution (in such calculation an assumption is made that c solution =   c water)        

- and m is mass of solution

- and ΔT is temperature change

1- now we need to Find mass of solution:

m solution = m(H2O)+ m(Na)-m(H2)m(H2O)

m H2O= V(H2O)*ρ(H2O)

             = 247 cm3*1g/cm3 = 247 gm

and m(Na)= 13 g

2- now we need to Find m(H2):

n(Na)(moles Na)= mass/Molar mass = 13g/23 g/mol = 0.57 mol.

According to equation mole ratio n(Na):n(H2)= 2:1,

then n(H2)=n(Na)/2

                =0.57/2=0.29 mol.

∴m(H2)= moles * molar mass

          =0.29 mol *2g/mol

          = 0.58 g

∴m solution= 247 g + 13 g – 0.58 g = 259.42 g

and when q=4.18 J/K g* 259.42 g *(339.7 K – 298 K)= 45218 J

The temperature of solution increased because heat was absorbed by the solution (q>0).

Then ΔHrxn= -q = -45218 J per 0.57 mol of Na

3- now we need to Find ΔHrxn per 1 mole of Na

ΔHrxn = -45218J/0.57 mol = -79331 J/mol ≈ -79 kJ/mol

4 0
3 years ago
Read 2 more answers
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