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Likurg_2 [28]
3 years ago
15

Bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter

nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. given that the atomic radii of h and cl are 25.0 cm and 100. pm , respectively, predict the bond length of the hcl molecule.

Chemistry
2 answers:
kirill [66]3 years ago
8 0
The lowest energy system occurs when the bond is the sum of the 2 atoms' radii. Therefore the length of the H-Cl bond is approximately:
25.0 pm + 100 pm = 125 pm
Hope this helps!
Alisiya [41]3 years ago
5 0

Answer:Hence, the bond length in HCl is 125 pm.

Explanation:

Bond length : It is an average distance between the nuclei of two bonded atoms in a molecule.

Also given that bond length is the distance between the centers of two bonded atoms. on the potential energy curve, the bond length is the inter-nuclear distance between the two atoms when the potential energy of the system reaches its lowest value. Beyond this if atoms come closer to each other then their will be repulsion between them.

So, the bond length between the Hydrogen and Chlorine atom in HCl molecule is :

Bond length=radius _{hydrogen}+radius_{chlorine}=25pm+100pm=125pm

Hence, the bond length in HCl is 125 pm.

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A mixture 21.7 g NaCl 3.74 g kcl and 9.76 g licl how many moles of nacl are in this mixture
slava [35]
Moles (mol) = mass (g) / molar mass (g/mol)

Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol

Hence moles of NaCl in the mixture is 0.372 mol.

Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.

mole % = (moles of desired substance / Total moles of the mixture) x 100%

Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

Total moles of mixture = moles of NaCl + KCl + LiCl

Mass of KCl = 3.74 g 
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g  / 74.6 g/mol = 0.050 mol

Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol

Total moles =  0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
                           = (0.372 mol / 0.652 mol) x 100%
                           = 57.06% 

Hence, mixture has 57.06% of NaCl as the mole percentage.
8 0
3 years ago
Please someone help I'm very confused
hoa [83]

Answer:

3.03 \: or \:  3\frac{1}{33} (in \: fration) \: hours

Explanation:

33 miles takes 1 hour

1 " " 1/33 "

100 " 100×1/33

3.03 hours

7 0
3 years ago
A sample of gas occupies 9.0 mL at a pressure of 500.0 mm Hg. A new volume of the same sample is at a pressure of 750.0 mm Hg.
telo118 [61]
Use the relatio P1V1=P2V2 ( p= pressure, v= volume)- assuming number of moles of gas and temperature are kept constant.

1.) A. Larger- pressure increases from 500mmHg to 750mmHg.

2.) B. Smaller

3.) B. 6.0mL
7 0
3 years ago
Which phrase describes properties of a solid?
Licemer1 [7]

Answer: fixed shape and volume

Explanation:

i took the quiz so its right

6 0
3 years ago
A 1.200 liter solution contains 35.0 grams of potassium iodide (KI). What is the molarity of this
enot [183]

Answer:

M = 0.177

Explanation:

First, we have to find the molar mass of potassium iodine (KI).

K = 39.098

I = 126.904

Now, add these values together to get the molar mass of KI

39.098 + 126.904 = 166.0028

Now, it's time to do a grams to moles conversion.

35.0 g KI * \frac{1 mol KI}{166.0028 g KI} = \frac{35.0}{166.0028} = 0.212 mol KI

Now, we can find the molarity of this solution.

Molarity (M) = \frac{mol}{L}

M = \frac{0.212 mol KI}{1.200 L} = 0.177 M

The molarity (M) of this solution is 0.177.

3 0
3 years ago
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