Answer:
Depending on the 
value of 
, the cell potential would be:
, using data from this particular question; or- approximately
, using data from the CRC handbooks.
Explanation:
In this galvanic cell, the following two reactions are going on:
- The conversion between
and 
ions, 
, and - The conversion between
and 
ions, 
.
Note that the standard reduction potential of ions to is higher than that of ions to . Alternatively, consider the fact that in the metal activity series, copper is more reactive than silver. Either way, the reaction is this cell will be spontaneous (and will generate a positive EMF) only if ions are reduced while is oxidized.
Therefore:
- The reduction reaction at the cathode will be: . The standard cell potential of this reaction (according to this question) is
. According to the 2012 CRC handbook, that value will be approximately 
.
- The oxidation at the anode will be:
. According to this question, this reaction in the opposite direction () has an electrode potential of 
. When that reaction is inverted, the electrode potential will also be inverted. Therefore, 
.
The cell potential is the sum of the electrode potentials at the cathode and at the anode:
.
Using data from the 1985 and 2012 CRC Handbook:
.
Answer:
All the matter that is made of atoms that cannot be broken or beaten into thin sheet .2All matters of a given book are in mass and mixture
The correct answer is c hypothesis
Answer:
See Explanation
Explanation:
Given that;
N/No = (1/2)^t/t1/2
Where;
No = amount of radioactive isotope originally present
N = A mount of radioactive isotope present at time t
t = time taken
t1/2 = half life
N/1000=(1/2)^3/6
N/1000=(1/2)^0.5
N = (1/2)^0.5 * 1000
N= 707 unstable nuclei
Since the value of the initial activity of the radioactive material was not given, the activity of the radioactive material after three months is given by;
Decay constant = 0.693/t1/2 = 0.693/6 months = 0.1155 month^-1
Hence;
A=Aoe^-kt
Where;
A = Activity after a time t
Ao = initial activity
k = decay constant
t = time taken
A = Aoe^-3 *0.1155
A=Aoe^-0.3465
