Moles (mol) = mass (g) / molar mass (g/mol)
Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol
Hence moles of NaCl in the mixture is 0.372 mol.
Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.
mole % = (moles of desired substance / Total moles of the mixture) x 100%
Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
Total moles of mixture = moles of NaCl + KCl + LiCl
Mass of KCl = 3.74 g
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g / 74.6 g/mol = 0.050 mol
Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol
Total moles = 0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
= (0.372 mol / 0.652 mol) x 100%
= 57.06%
Hence, mixture has 57.06% of NaCl as the mole percentage.
Use the relatio P1V1=P2V2 ( p= pressure, v= volume)- assuming number of moles of gas and temperature are kept constant.
1.) A. Larger- pressure increases from 500mmHg to 750mmHg.
2.) B. Smaller
3.) B. 6.0mL
Answer: fixed shape and volume
Explanation:
i took the quiz so its right
Answer:
M = 0.177
Explanation:
First, we have to find the molar mass of potassium iodine (KI).
K = 39.098
I = 126.904
Now, add these values together to get the molar mass of KI
39.098 + 126.904 = 166.0028
Now, it's time to do a grams to moles conversion.
35.0 g KI *
=
= 0.212 mol KI
Now, we can find the molarity of this solution.
Molarity (M) = 
M =
= 0.177 M
The molarity (M) of this solution is 0.177.