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geniusboy [140]
3 years ago
6

List the 4 main components of air in their molecular form.

Chemistry
1 answer:
ICE Princess25 [194]3 years ago
3 0

Answer:

Air is made up of 78.09% nitrogen, 20.95% oxygen, 0.93% argon, 0.04% carbon dioxide, and other gases in meager amounts.

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When baking soda (sodium bicarbonate or sodium hydrogen carbonate, NaHCO3) is heated, it releases carbon dioxide gas, which is r
MariettaO [177]

Answer:

a. NaHCO₃ + HCl → NaCl + H₂O + CO₂

b. 39.14 g is the mass of NaHCO₃ required to produce 20.5 moles of CO₂

Explanation:

A possible reaction for NaHCO₃ to make dioxide is this one, when it reacts with hydrochloric to produce the mentioned gas.

NaHCO₃ + HCl → NaCl + H₂O + CO₂

Ratio in this reaction is 1:1

So 1 mol of baking soda, produce 1 mol of CO₂

Let's calculate the moles

20.5 g CO₂ / 44 g/m = 0.466 moles

This moles of gas came from the same moles of salt.

Molar mass baking soda = 84 g/m

Molar mass . moles = mass

84 g/m .  0.466 moles = 39.14 g

4 0
4 years ago
PLEASE HELP!!! HOW DO I DO THIS??
Effectus [21]
4.7 is the answer!

Mark me brainiest
7 0
2 years ago
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
3 years ago
Sodium chloride, NaCl, is formed when a sodium atom transfers its electron to a chlorine atom. The difference in charge between
BARSIC [14]

Answer:

nuclear

Explanation:

7 0
3 years ago
A chemist prepares a solution of aluminum sulfate (Al2(SO4) by weighing out 116.0 g of aluminum sulfate into a 450. mL volumetri
trasher [3.6K]

Answer:

0.0733 mol /dL

Explanation:

Mole -

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the information of the question ,

w = 116.0 g

As we know, molecular mass of aluminum sulfate ,

m = 342.15 g/mol

n = w / m  

n = 116.0 g /  342.15 g/mol = 0.33 mol

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

The unit is mol / L ,

Hence , from the question, the value of molarity is asked ,

From the information of the question ,

V = 450 mL ,

Since,

1 mL = 0.01 dL

As, the unit asked in the question is in dL,

V = 4.5 dL

n = 0.33 mol ( as calculated above )

Using the above formula ,

M = n / V  

M = 0.33 mol / 4.5 dL

M = 0.0733 mol /dL

M =

5 0
3 years ago
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