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3 years ago

Does anyone know how to solve this

Mathematics

2 answers:

Dvinal [7]3 years ago

6 0

Answer:

240

Step-by-step explanation:

Substitute the given values for the variables, and evaluate the expressions.

n = -5; m = 4

2n² - m = 2(-5)² - 4 = 2(25) - 4 = 50 - 4 = 46

H = 60; Q = 40; V = 10

HQV/100 = (60)(40)(10)/100 = 6(4)(10) = 240

ki77a [65]3 years ago

5 0

Answer:

240

Step-by-step explanation:

1) Put n = -5 and m = 4 into the equation, you'll then have;

2(-5)²-4

2(25)-4

50-4=46

2) Put H=60, Q=40 and V=10 into the equation, then you'll have that;

(60×40×10)/100

24000/100

=240

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Answer:

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General Formulas and Concepts:

Algebra I

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Calculus

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

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Step-by-step explanation:

Step 1: Define

$\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx$

Step 2: Integrate Pt. 1

[Integral] Factor fraction denominator: $\displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx$
[Integral] Integration Property - Multiplied Constant: $\displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx$

Step 3: Identify Variables

Set up u-substitution for the arctan trig integration.

$\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx$

Step 4: Integrate Pt. 2

[Integral] Substitute u-du: $\displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du$
[Integral] Trig Integration: $\displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C$
[Integral] Simplify: $\displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C$
[integral] Multiply: $\displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C$
[Integral] Back-Substitute: $\displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C$