Answer:
31.3grams
Explanation:
The amount of a radioactive element that remains, N(t), can be calculated by using the formula;
N(t) = N(o) × 0.5^{t/t(1/2)}
Where;
N(t) = mass of substance remaining
N(o) = mass of original substance
t(1/2) = half-life of substance
t = time elapsed
From the provided information; N(t) = ?, N(o) = 250g, t(1/2) = 1599 years, t = 4797 years
N(t) = 250 × 0.5^{4797/1599}
N(t) = 250 × 0.5^(3)
N(t) = 250 × 0.125
N(t) = 31.25g
N(t) = 31.3grams
Answer:
The answer is
<h2>190.32 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of ethanol = 146.4 mL
Density = 1.3 g/mL
The mass is
mass = 1.3 × 146.4
We have the final answer as
<h3>190.32 g</h3>
Hope this helps you
Answer:
Hydrogen bonding.
Explanation:
Ammonium lauryl sulfate is also known as ammonium dodecyl sulfate there are two parts in Ammonium lauryl sulfate one is nonpolar hydrocarbon and other part polar sulfate group.
Due to polarity of sulfate group its form hydrogen bond very easily.
It is mainly used as foaming agent the main reason of its use is very much soluble in water and making hydrogen bond with water.
Ok, so first we'll start by rearranging the formula.
Subtract log10 Xo from both sides to get
log10 Xf - log10 Xo = nlog10 0.5
Then using log properties you have
log10 (Xf/Xo) = nlog10 0.5
Using another log property we have
log10 (Xf/Xo) = log10 0.5^n
Now we can do
10 ^ (log 10 (Xf/Xo) ) = 10 ^ (log10 0.5^n)
which we evaluate to be
Xf/Xo = 0.5^n
Now we can do
log0.5 (Xf/Xo) = n
Answer:there butt and other stuff you know what I am saying
Explanation: