Answer:
a ) π/2, 4π/3, 3π/2. 5π/3.
Step-by-step explanation:
2 sin t cos t + √3 cos t = 0
cos t ( 2 sin t + √3 ) = 0
Therefore:
cos t = 0, t 1 = π/2, t 2 = 3 π/2
or:
2 sin t + √3 = 0
2 sin t = - √3
sin t = - √3 / 2
t 3 = 4 π/3, t 4 = 5 π/3
Answer:
<h2>a) (5, 11)</h2><h2>b) r = 9</h2><h2>c) (-4, 11)</h2>
Step-by-step explanation:
The equation of a circle in standard form:
(h, k) - center
r - radius
We have the equation:
Therefore
a) h = 5, k = 11 → the center (5, 11)
b) r² = 81 → r = √81 = 9 - radius
c) We choose any value of x, but one which h - r ≤ x ≤ h + r
5 - 9 = -4
5 + 9 = 14
-4 ≤ x ≤ 14
Let x = -4. Put to the equation and solve for y:
<em>subtract 81 from both sides</em>
<em>add 11 to both sides</em>
(-4, 11)
Answer:
-2x-2
For a line equation for the form of y = mx +b, the slope is m
m= -2
The function has no undefined points nor domain
constraints. There fore, the domain is
domain: -∞<x<∞
The range of polynomial with odd degrees is all the real numbers
range: -∞<f(x)<∞
Step-by-step explanation:
graph is inserted