Question

P= $790, t= 3, r=4% compounded continuously : Find A

Answer 1

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \ 790\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ t=years\to &3 \end{cases} \\\\\\ A=790e^{0.04\cdot 3}\implies A=790e^{0.12}$