P= $790, t= 3, r=4% compounded continuously : Find A

1 answer:

8 0

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$790\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
t=years\to &3
\end{cases}
\\\\\\
A=790e^{0.04\cdot 3}\implies A=790e^{0.12}$

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