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2 years ago

How do you delete a question

Mathematics

1 answer:

Alina [70]2 years ago

3 0

Answer:

you have to try to delete it before five minutes and in that time you'll see three dots beside the question tap it and you will be able to delete it

Step-by-step explanation:

or I think that's how you do it because I deleted an answer that way

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Find the value of x if mPYA 12x 20 and m LPLA 110O 220O 240O 20O 40

romanna [79]

M<PLA = 1/2 m PYA
110 = 1/2 (12x - 20)
12x - 20 = 220
12x = 220 + 20 = 240
x = 240 / 12 = 20

4 0

4 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$

Since

$\int\limits^1_0 {x^{2} } \, dx = 13$ ,

Substituting this into the equation the equation, we have

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Learn more about definite integrals here:

brainly.com/question/17074932

4 0

2 years ago

Find an equivalent ratio in simplest terms:<br> 12 : 32

jarptica [38.1K]

Answer:

3:8 i think

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

4x=5x-12 what does x equal

Stels [109]

4x = 5x - 12

First you want to subtract 5x from both sides:

5x will cancel out

4x - 5 = -1

Next you want to divide -1 on both sides:

-1 will cancel out

-12/-1 = 12

Since there are two negatives it turns into a positive.

So your answer is x = 12.

Hope this Helps!!

3 0

3 years ago

Read 2 more answers

How can you restrict the domain of the function f(x)=|x+4|-2 so the range of the inverse function f^-1(x),is [-4, )

wariber [46]

The range of the inverse has to match the domain of the original function. We want to have $f^{-1}(x)$ map to $[-4,\infty)$ , so we restrict the domain of $f(x)$ to this interval.

5 0

3 years ago