Answer:
Bacteria can use sexual and asexual repoduction
Explanation:
Answer:
Metallic character decreases, and electronegativity increases.
Explanation:
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In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.
Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.
Thus, the answer would be: "Metallic character decreases, and electronegativity increases".
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The chemical formula of the ionic compound is XY₂.
<h3>Ionic compounds</h3>
- Ionic compounds are compounds which are formed from the combination of negatively charged and positively charged ion.
- Positively charged ions are formed by loss of electrons
- Negatively-charged ions are formed from gain of electrons
<h3>Formation of ionic compounds</h3>
During the formation of the ionic compound between an ion X that has a charge of 2+ and ion Y has a charge of 1-, two negatively charged ions of Y are required to form a neutral ionic ionic compound when they react with X.
The chemical the formula of the ionic compound they form is as follows;
X²⁺ + 2Y⁻ ---> XY₂
Therefore, the chemical formula of the ionic compound is XY₂.
Learn more about ionic compounds at: brainly.com/question/13439771
The maximum negative displacement of a wave is the same as its amplitude.
As a wave travels through space, its particles are sometimes above the
<em>x</em>-axis (+) and sometimes below it (-).
The maximum displacement from the axis is the <em>amplitude</em> of the wave.
The amplitude of the wave is the <em>same in both the positive and negative directions</em>.
Answer is: pH of hydroxylamine solution is 9,23.
Kb(NH₂OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₂OH)<span> = 0,0500 M =
0,05 mol/L.
c(NH</span>₂⁺) = c(OH⁻) = x.
c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).
0,0000000066 = x² / (0,05 mol/L - x).
solve quadratic equation: x = c(OH⁻) = 0,000018 mol/L.<span>
pOH = -log(</span>0,000018 mol/L) = 4,74.<span>
pH = 14 - 4,74 = 9,23.</span>
