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Oksanka [162]
3 years ago
14

Did I get the answer correct, and could someone possibly explain?

Chemistry
1 answer:
Arada [10]3 years ago
6 0
Yes that should be correct
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What are the n, l, and possible ml values for the 2p and 5f sublevels?
elixir [45]

Answer:

1. 2p sublevels, n = 2, orbital <em>p</em>, l = 1, ml = 0, ±1

2. 5f sublevels n = 5, orbital <em>f</em>, l = 3, ml = 0, ±1, ±2, ±3

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Subshell number, 0 ≤ l ≤ n − 1

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

So,

1. 2p sublevels,

n = 2, orbital <em>p</em>, so l = 1, ml = 0, ±1

2. 5f sublevels

n = 5, orbital <em>f</em>, so l = 3, ml = 0, ±1, ±2, ±3

7 0
2 years ago
The destructive force of waves is not felt while they are out at sea, in the open ocean, but it is felt when they do what?
PIT_PIT [208]

Answer: Come Onshore

Explanation:

Sea waves are harmless when present at Sea. However, it becomes DESTRUCTIVE as it travels to the land surface.

Its effects include the sweeping off (erosion) of features, BENEFICIAL soil organisms and the transport of sand and sediment along coastal areas which might include farms, residential houses etc.

Thus, the effects of Sea waves ONSHORE affects the following: agricultural activities

Domestic activities

Environmental balance etc.

6 0
3 years ago
Read 2 more answers
what concentration in parts per million in a solution that contains .008 grams of o2 dissolved in 1000 grams of water
julia-pushkina [17]
Ppm = mass of solute mg / mass of solvent kg

0.008 * 1000 =  8.0 mg ( solute )

1000 / 1000 = 1.0 kg (solvent )

ppm = 8 / 1

= 8.0 ppm

hope this helps!
7 0
3 years ago
Find the no of atoms of Fe in 2 moles of Fe<br>​
steposvetlana [31]

Answer:

1mole of any substance contains 6.022x10²³atoms

2moles of Fe will contain

2x6.022x10²³atoms = 1.204x10²⁴atoms.

Have a Great day!

7 0
2 years ago
The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The c
dem82 [27]

Answer:

The work is  

      W = -0.369kJ

The energy  change of the reaction is  \Delta U _{rxn} = 43.839 kJ  

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             2 Cu_2 O + O_2_{(g)} ----> 4 CuO_{(s)}

     The mass of  Cu_2 O is  m = 42.60g

      The enthalpy Cu_2 O is  \Delta H_{re} = -43.47 \ kJ this also the change in energy in terms of heat

      The pressure at which it is oxidized is P = 1\  bar

The  no of moles of Cu_2 Oused in this reaction is mathematically represented as

        n = \frac{mass \ of   \ Cu_2 O}{Molar \ mass \  of   \ Cu_2 O}

The molar mass of Cu_2 O is  a constant with a value  M = 143.1 g/mol

   Now substituting values

             n = \frac{ 42.60}{143.1}

            n = 0.29769 \ moles

From the reaction we see that

Two mole of Cu_2 O  reacts with One mole of O_2 to give Four moles of  CuO_{(s)}

This means that

One mole of  Cu_2 O  reacts with 0.5 mole of O_2 to give two moles of  CuO_{(s)}

it also implies that

0.29769 \ mole of  Cu_2 O  reacts with 0.5 * 0.29769 moles of O_2 to give 2* 0.29769 moles of  CuO_{(s)}

so

0.29769 \ mole of  Cu_2 O  reacts with 0.149 moles of O_2 to give 0.595 moles of  CuO_{(s)}

Now the number of moles of gaseous reactant is

      N_{O_2} = 0.149 \ moles

The number of moles of gaseous product  is

     N_p = 0 \ moles

So the change in number of moles for gaseous  compounds is mathematically evaluated as

         \Delta N = 0- 0.149 \ moles

        \Delta N = - 0.149 \ moles

Now the workdone for  the compound Cu_2 O is mathematically represented as

        W = \Delta N RT

Where R is the gas constant with a value of R = 8.314 J/mol \cdot K

            T is the temperature with a value  T = 25 + 273 = 298 K

     Substituting values

     W = -0.149 * 8.314 * (298)

     W = -0.369kJ

Generally the internal energy change of the reaction can be represented as

           \Delta U _{rxn} = \Delta H_{re} - W

Substituting value

        \Delta U _{rxn} = -43.47 -  (-0.369)

        \Delta U _{rxn} = 43.839 kJ  

This is the internal energy change on the reaction for 42.60 g of Cu_2 O

       

3 0
3 years ago
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