How many total atoms are there in 69.1 g of ammonia (NH3)?
1 answer:
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Answer:
The combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
Explanation:
Given;
CH₄ + 2O₂ → CO₂ + 2H₂O, ΔH = -890 kJ/mol
From the combustion reaction above, it can be observed that;
1 mole of methane (CH₄) released 890 kilojoules of energy.
Now, we convert 59.7 grams of methane to moles
CH₄ = 12 + (1x4) = 16 g/mol
59.7 g of CH₄
1 mole of methane (CH₄) released 890 kilojoules of energy
3.73125 moles of methane (CH₄) will release ?
= 3.73125 moles x -890 kJ/mol
= -3320.81 kJ
Therefore, the combustion of 59.7 grams of methane releases 3320.81 kilojoules of energy
<u>Answer:</u> The frequency of the radiation is 33.9 THz
<u>Explanation:</u>
We are given:
Wave number of the radiation,
Wave number is defined as the number of wavelengths per unit length.
Mathematically,
where,
= wave number =
= wavelength of the radiation = ?
Putting values in above equation, we get:
Converting this into meters, we use the conversion factor:
1 m = 100 cm
So,
- The relation between frequency and wavelength is given as:
where,
c = the speed of light =
= frequency of the radiation = ?
Putting values in above equation, we get:
Converting this into tera Hertz, we use the conversion factor:
So,
Hence, the frequency of the radiation is 33.9 THz