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3 years ago

Plz help will mark brainliest

Physics

2 answers:

Ksenya-84 [330]3 years ago

7 0

Answer: 18 cm

Explanation:

Anastasy [175]3 years ago

3 0

Explanation:

The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.

We have to take moments around the pivoted point.

Moment = Force × Perpendicular distance to the force

For the rod to be in equilibrium,

Clockwise moment - Anticlockwise moment = 0

Clockwise moment = Anticlockwise moment

The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm

So 20 cm× 1.2 N produces a Clockwise moment

If Perpendicular distance between pivoted point and 2N load is x,

Anticlockwise moment = x × 2N

20 cm× 1.2N = 2N × x

x = 12 cm

So 2 N load is at 12 from the pivoted point.

From the left edge of the meter ruler, 2N load is at 30-12 cm distance

= 18 cm

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yulyashka [42]

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$v = 60 mph$

now this speed in SI units given as

$v = 60 \times \frac{1609 m}{3600 s}$

$v = 26.82 m/s$

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so here we will have

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now we have

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3 years ago

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3 years ago

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2 years ago

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Nimfa-mama [501]

The strength of the magnetic field is equal to 20 Tesla.

<h3>Explanation:</h3>

Given:

Induced potential difference = V = 12 V

Length of wire = L = 0.20 m

Speed of the moving wire = V = 3.0 m/s

Magnetic field strength = B = ?

A conductor, placed in a uniform magnetic field; when moved at a constant speed with respect to the field, leads to a changing magnetic flux, generating an electromotive force (EMF). Using, Faraday's law of magnetic induction, a moving conductor's induced EMF in terms of the magnetic field strength is given by :

$E = L\times V\times B$ ......................(1)

where

E = Induced potential difference (EMF)

L = Length of the conductor

V = Speed of the conductor moved with respect to the magnetic field

B = Strength of uniform magnetic field

Rewriting equation (1) for B, we get

$B = \frac{E}{L\times V} = \frac{12}{0.2\times 3} = \frac{12}{0.6} = 20\ T$

The strength of magnetic field is equal to 20 Tesla.

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4 years ago

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a co

Igoryamba

Answer:

a. before

Explanation:

Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?

from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .

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before the displacement was maximum at 2mm was instant at time=0.04s.

But later was constant at 0.06s at a displacement point of 1mm

4 0

4 years ago

Plz help will mark brainliest ​

Plz help will mark brainliest