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4 years ago

How did world cup soccer become cool?

1 answer:

5 0

It became cool because many people who likes ⚽️ soccer felt it atrcting and then they spreaded the world cup out and then people started.likeing it slot

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The change in a pitch of a sound as an object moves closer or farther away is a result of

MrMuchimi

The Doppler effect is a change in the frequency of sound waves that occurs when the source of the sound waves is moving relative to a stationary listener. As the source of sound waves approaches a listener, the sound waves get closer together, increasing their frequency and the pitch of the sound.

I’m hope this help

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3 years ago

Which statement does NOT describe redesign?

pantera1 [17]

D. It happens all the time

4 0

3 years ago

Velocity

morpeh [17]

Velocity is not changing.

Acceleration is zero.

Net force is zero.

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3 years ago

Read 2 more answers

A thin soap bubble of index of refraction 1.33 is viewed with light of wavelength 550.0nm and appears very bright. Predict a pos

faust18 [17]

Answer:

The possible thickness of the soap bubble = $1.034\times 10^{-7}\ m.$

Explanation:

<u>Given:</u>

Refractive index of the soap bubble, $\mu=1.33.$
Wavelength of the light taken, $\lambda = 550.0\ nm = 550.0\times 10^{-9}\ m.$

Let the thickness of the soap bubble be $t$ .

It is given that the soap bubble appears very bright, it means, there is a constructive interference takes place.

For the constructive interference of light through a thin film ( soap bubble), the condition of constructive interference is given as:

$2\mu t=\left ( m+\dfrac 12 \right )\lambda.$

where $m$ is the order of constructive interference.

Since the soap bubble is appearing very bright, the order should be 0, as $0^{th}$ order interference has maximum intensity.

Thus,

$2\mu t=\left (0+\dfrac 12\right )\lambda\\t=\dfrac{\lambda}{4\mu}\\\ \ = \dfrac{550\times 10^{-9}}{4\times 1.33}\\\ \ = 1.034\times 10^{-7}\ m.$

It is the possible thickness of the soap bubble.

6 0

3 years ago

Two small, positively charged spheres have a combined charge of 5.23 x 10^-5 C. If each sphere is repelled from the other by an

pshichka [43]

Answer:

The smallest charge of the dial is 2.46 10-5 C

Explanation:

The Coulomb force is responsible for the electroactive repulsion, the equation that describes it is

F = k q1 q2 / r²

Where K is the Coulomb constant that is worth 8.99109 N m² / C², q is the electric charge of each sphere and r is the distance between them.

They also give us the condition that the sum of the charge is 5.23 10-5 C

Qt = q1 + q2 = 5.23 10⁻⁵ C

Let's replace in the Coulomb equation, let's clear and calculate

F = k (Qt -q2) q2 / r²

F = k q22 / r² - k Qt q2 / r²

1.0 = 8.99 10⁹ q2² /2.04² - 8.99 10⁹ 5.23 10⁻⁵ q2 / 2.04²

1.0 = 2.16 10⁹ q2²2 - 11.30 10⁴ q2

0 = 2.16 109 q2² - 11.30 10⁴ q2 -1.0 (* 1/2.16 109)

0 = q2² - 1.05 10⁻⁵ q2 - 0.463 10⁻⁹

Let's solve the second degree equation for q2

q2 = 1.05 10⁻⁵ ±√[(1.05 10⁻⁵)² - 4 1 (-0.463 10⁻⁹)] / 2

q2 = 1.05 10⁻⁵ ±√ [1.10 10⁻¹⁰ + 18.52 10⁻¹⁰] / 2

q2 = {1.05 10⁻⁵ ± 4.43 10⁻⁵} / 2

The solutions are

q2 ’= 2.74 10-5 C

q2 ’’ = -1.69 10-5 C

As the problem tells us that the spheres are positively charged, the correct solution is 2.74 10-5 C, let's see the charge of the other sphere

Qt = q1 + q2 ’

q1 = Qt -q2 ’

q1 = 5.23 10-5 - 2.74 10-5

q1 = 2.46 10-5 C

The smallest charge of the dial is 2.46 10-5 C

5 0

4 years ago