No map given but it shouldn't matter.
E is the 5th letter, L the 12th.
Start at S(6,12). End at E(10,5)
The vector between them, E-S=(4,-7)
Each unit is 1/16 of a mile, though that probably doesn't matter that much.
Doug has to stay on the grid, so has to run |4|+|7|=11 units. At 30 mi/hr that takes (11/16)/30 = 0.022916 hours.
Bert can go diagonally, so flies √(4²+7²)=√65 ≈ 8.06 units. At 20 mi/hr that takes (8.06/16)/20 = 0.025194 hours.
Answer: Doug wins
Why? Because it's quicker to cover 4+7 at 30 mph than it is to cover √(4²+7²) at 20 mph. That is, Doug is 1.5 times faster and the 1.5 times the diagonal distance is more than the grid distance.
Answer:
46
Step-by-step explanation:
The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.
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<h3>Pythagorean theorem</h3>
The relation between the leg lengths (a, b) and the hypotenuse (c) is ...
c² = a² +b²
Solving for b gives ...
b = √(c² -a²)
<h3>application</h3>
In this problem, we have c=55 and a=30. Then the width of the TV is ...
b = √(55² -30²) = √(3025 -900) = √2125
b ≈ 46.098
The width of the TV is about 46.
Start with the answer format we want, and work your way toward forming a single fraction like so

Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.
Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.
So, 4+b = 1 leads to b = -3
Therefore, a = 2 and b = -3
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An alternative route:

I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.
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Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.
Answer:
<u>Principal</u><u> </u><u>is</u><u> </u><u>$</u><u>1</u><u>0</u><u>0</u><u>0</u>
Step-by-step explanation:
• From the formular of simple interest:

• substitute and find the principal:
