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3 years ago

Where could light travel the easiest and fastest?

Physics

2 answers:

Alex3 years ago

8 0

Answer:

try through air

Explanation:

madreJ [45]3 years ago

3 0

Explanation:

Light travels fastest through air

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A conducting rod is moving through a magnetic field, as in the drawing. The magnetic field strength is 0.65 T, and the speed of

Contact [7]

Explanation:

The given data is as follows.

Magnetic field strength (B) = 0.65 T

Speed (v) = 2.3 m/s

Induced emf (E) = ?

Formula for emf induced at the ends of the rod of length L which is moving with a speed of v is as follows.

E = BvL

Putting the given values into the formula as follows.

$E_{1} = BvL$

= $0.65 T \times 2.3 m/s \times L$

= 1.495 L .............. (1)

When magnetic field is changed to $B_{2}$ = 0.48 T

Now, we assume that the speed be $v_{2}$ to get the emf $E_{2} = E_{1}$ .

Then, $0.48 T \times v_{2} \times L = 0.65 T \times 2.3 m/s \times L$

$v_{2}$ = 3.11 m/s

Therefore, we can conclude that the speed v of the rod be adjusted to reestablish the emf induced between the ends of the rod at its initial value is 3.11 m/s.

6 0

3 years ago

Which of the following is NOT an important physical property of matter?

Xelga [282]

Volume isn't a property of matter at all. You can have a big lump or a tiny lump of the same substance.

5 0

3 years ago

A car of mass 1000 kg is moving at 25 m/s. It collides with a car of mass 1200 kg moving at 30 m/s. When the cars collide, they

Alinara [238K]

Answer:

The total momentum of the cars before the collision is 61,000 kg.m/s

The total momentum of the cars after the collision is 61,000 kg.m/s

The velocity of the cars after the collision is 27.727 m/s

Explanation:

Given;

mass of the first car, m₁ = 1000 kg

initial velocity of the car, u₁ = 25 m/s

mass of the second car, m₂ = 1200 kg

initial velocity of the second car, u₂ = 30 m/s

The common velocity of the cars after collision = v

The total momentum of the cars before collision is calculated as;

P₁ = m₁u₁ + m₂u₂

P₁ = (1000 x 25) + (1200 x 30)

P₁ = 61,000 kg.m/s

The total momentum of the cars after collision is calculated as;

P₂ = m₁v + m₂v

where;

v is the common velocities of the cars after collision since they stick together.

P₂ = v(m₁ + m₂)

To determine "v" apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(1000 x 25) + (1200 x 30) = v(1000 + 1200)

61,000 = 2,200v

v = 61,000/2,200

v = 27.727 m/s

The total momentum after collsion = v(m₁ + m₂)

= 27.727(1000 + 1200)

= 61,000 kg.m/s

Thus, momentum before and after collsion are equal.

8 0

3 years ago

Jenny and Betty are having a great time at Busch Gardens riding the Ubanga Banga bumper cars. Jenny, who is traveling southward

lutik1710 [3]

They both exert an equal amount of force onto each other

7 0

4 years ago

1.) How much potential energy does an object with a mass of 3 kg have on top of a stand 12 meters

Elena-2011 [213]

Answer:

<h2>352.8 Joules</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 3 × 9.8 × 12

We have the final answer as

Hope this helps you

7 0

3 years ago