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Katena32 [7]
3 years ago
5

Where could light travel the easiest and fastest?

Physics
2 answers:
Alex3 years ago
8 0

Answer:

try through air

Explanation:

madreJ [45]3 years ago
3 0

Explanation:

Light travels fastest through air

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Calculate the KE of a car which has a mass of 1000 kg and is moving at the rate of 20 m/s
Elan Coil [88]

Answer:

The kinetic energy of the car is 2.0\cdot 10^5 J

Explanation:

3 0
2 years ago
A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in
sukhopar [10]

Answer:

The final temperature of the element = 262.67°C

The power dissipated in the heating element initially = 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A = 147.60 W

Explanation:

Our given parameters include;

A Nichrome heating element operates on 120 V.

Voltage (V) = 120V

Initial Current (I₁) = 1.36 A

Initial Temperature (T₁) = 28°C

Final Current (I₂) = 1.23 A

Final Temperature (T₂) = unknown ????

Temperature dependencies of resistance is given by:

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]            ----------------------    (1)

in which R₁ is the resistance at temperature T₁

R_{T(2) is the resistance at temperature T₂

Given that V= IR

R = \frac{V}{I}

Therefore, the resistance at temperature 28°C is;

R_{28}= \frac{120V}{1.36A}

= 88.24Ω

R_{T(2) = \frac{120V}{1.23A}

= 97.56Ω

From (1) above;

R_{T(2)}=R_1[1+\alpha (T_2-T_1)]      

97.56 = 88.24 [ 1 + 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)]

\frac{97.56}{88.24}= 1+(4.5*10^{-4})(T-28^0C)

1.1056 - 1 = 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)

0.1056 = 4.5×10⁻⁴(T₂-28°C)

\frac{0.1056}{4.5*10^{-4}}= T-28^0C

T - 28° C = 234.67

T = 234.67 + 28° C

T = 262.67 ° C

(b)

What is the power dissipated in the heating element initially and when the current reaches 1.23 A

The power dissipated in the heating element initially can be calculated as:

P = I²₁R₂₈

P = (1.36A)²(88.24Ω)

P = 163.209 W

P ≅ 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A can be calculated as:

P= I^2_2R_{T^0C

P = (1.23)²(97.56Ω)

P = 147.598524

P ≅ 147.60 W

6 0
3 years ago
Which of the following are examples of projectile motion?
denis-greek [22]

Answer:

A or C    I would pick C

Explanation:

8 0
4 years ago
Read 2 more answers
the amplitude of the wave is which of the following A. Resonance B. Reflection C. Energy D. Magnitude
OLga [1]
D.Magnitude is the answer
8 0
4 years ago
Can someone help me please
TEA [102]

Answer:

D

Explanation:

Because it is impossible for it to show the real depth of the ocean and how deep it is

8 0
3 years ago
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