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Ivan
3 years ago
10

Jenny and Betty are having a great time at Busch Gardens riding the Ubanga Banga bumper cars. Jenny, who is traveling southward

in her bumper car, aims her car toward Betty, who is traveling northward in her bumper car. The cars collide and briefly come to a stop. What can you say about the magnitude of the force that Jenny's car exerts on Betty's car versus the magnitude of the force that Betty's car exerts on Jenny's car?
Physics
1 answer:
lutik1710 [3]3 years ago
7 0
They both exert an equal amount of force onto each other

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Pls help meeee!!! will mark brainliest!!​
Vitek1552 [10]

Answer:

water

is missing in above equation

hope it helps

5 0
2 years ago
Need help on these 2 questions please????? Hurry
fredd [130]

Answer:

Question 1 the anwser is 300 meters.  Question 2 the answer is speed.

is Explanation:

3 0
3 years ago
A closed, uninsulated system fitted with movable piston, so no matter is exchanged with the surroundings, was assembled. Introdu
xeze [42]

Answer: You do not specify what is being asked for. ∆E? ∆H?

∆E = (430 - 238) J = 192 J

∆H = 430 J

Explanation:

If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.

Therefore ∆H = 430 J

If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w

The question states that 238 J of work are done AND the system expanded

(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)

Therefore, ∆E = (430 - 238) J = 192 J

8 0
2 years ago
Convert 10095 mm to pm​
ludmilkaskok [199]

Answer:

1.01 × 1013 picometres

Explanation:

multiply the length value by 1e+9

3 0
2 years ago
h(t) = - 16t2 + 64t + 112 where t is the time in seconds. After how many seconds does the arrow reach it maximum height? Round t
laila [671]

Answer:

2 seconds

Explanation:

The function of height is given in form of time. For maximum height, we need to use the concept of maxima and minima of differentiation.

h(t)=-16t^{2}+64t+112

Differentiate with respect to t on both the sides, we get

\frac{dh}{dt}=-32t+64

For maxima and minima, put the value of dh / dt is equal to zero. we get

- 32 t + 64 = 0

t = 2 second

Thus, the arrow reaches at maximum height after 2 seconds.

8 0
3 years ago
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