Answer:131
Step-by-step explanation:
hope this helps <3
Let the value of the vehicle be described by the equation
V = a + bx
where x = number of years since purchase
a,b are constants.
When x = 0, V = $7500. Therefore
a + b*0 = 7500
a = 7500
When x = 7, V = $500. Therefore
7500 + 7b = 500
7b = 500 -7500 = -7000
b = -7000/7 = -1000
The equation is
V = 7500 - 1000x
The slope of this equation is the depreciation rate, and it is -$1000 per year.
Answer: $1000 depreciation per year.
28x + 44y = 964.40
21x + 33y = 723.30
Let's multiply the first equation by 4 and the second by -4
84x + 176y = 3857.6
-84x - 132y = -2893.2
Add the equations together.
0 + 44y = 964.4
Simplify
44y = 964.4
Divide both sides by 44
y = 964.4/44
Since we have the value of y, let's plug 964.4/44 into y for the first equation.
28x + 44(964.4/44) = 964.40
Simplify the left side
28x + 964.4 = 964.4
Subtract 964.4 from both sides
28x = 0
Divide both sides by 0
x = 0
In conclusion,
y = 964.4/44
x = 0
Answer: 63/2π
Step-by-step explanation: C=πd
63=πd
D=63/π
r=1/2d
1/2×63/π=<u>63/2π</u>
Answer:
It would be negative
Explanation:
