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3 years ago

Question 9 (1 point)

Chemistry

2 answers:

Bond [772]3 years ago

8 0

Answer:

Explanation:

Dependent and Independent variables are variables in mathematical modeling, statistical modeling and experimental sciences. Dependent variables receive this name because, in an experiment, their values are studied under the supposition or demand that they depend, by some law or rule, on the values of other variables.

Kaylis [27]3 years ago

6 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The Independent variable here is ~

time

And the dependent variable is ~

score on the final test

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What is 31 degrees Celsius in Fahrenheit

vovangra [49]

87.8 , 31 Celsius=87.8(88) in Fahrenheit

7 0

3 years ago

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URGENT !! A substance has 55.80% carbon, 7.04% Hydrogen, and 37.16% Oxygen. What is it's empirical and molecular formula if it h

Ede4ka [16]

<h3><u>Answer;</u></h3>

Empirical formula = C₂H₃O

Molecular formula = C₁₄H₂₁O₇

<h3><u>Explanation</u>;</h3>

Empirical formula

Moles of;

Carbon = 55.8 /12 = 4.65 moles

Hydrogen = 7.04/ 1 = 7.04 moles

Oxygen = 37.16/ 16 = 2.3225 moles

We then get the mole ratio;

4.65/2.3225 = 2.0

7.04/2.3225 = 3.0

2.3225/2.3225 = 1.0

Therefore;

The empirical formula = <u>C₂H₃O</u>

Molecular formula;

(C2H3O)n = 301.35 g

(12 ×2 + 3× 1 + 16×1)n = 301.35

43n = 301.35

n = 7

Therefore;

Molecular formula = (C2H3O)7

<u> = C₁₄H₂₁O₇</u>

6 0

4 years ago

Based on the information, what is the balanced chemical equation representing the burning of butane?

kompoz [17]

Answer:

OptionA. 2C4H10 + 13O2 —> 8CO2 + 10H20

Explanation:

Butane burns is air (O2) according to the equation:

C4H10 + O2 —> CO2 + H20

Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;

There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:

C4H10 + O2 —> 4CO2 + H20

Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:

C4H10 + O2 —> 4CO2 + 5H20

Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2

as shown below

C4H10 + 13/2O2 —> 4CO2 + 5H20

Now we multiply through by 2 clear off the fraction and we obtained:

2C4H10 + 13O2 —> 8CO2 + 10H20

6 0

4 years ago

If ch4 and c4h8 are released simultaneously at ends of a 50.0cm long glass tube, at what distance from the left end of the tube

Keith_Richards [23]

Answer:

They meet at the distance of 32.5 cm

Explanation:

The rate of diffusion is inversely proportional to the molar mass of gases.

If diffusion is represented as d and mass of gases as M. Then , rate is given as:

$d=k\sqrt{\frac{1}{M}}$

For , two gases

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

First , Calculate the ,molar mass of each gas :

CH4 = 1 (mass of C) + 4(mass of H)

= 1(12)+4(1)

= 12 + 4 = 16 gram

M1 = 16 gram

C4H8 = 4(mass of C) + 8(Mass of H)

= 4(12) + 8(1)

= 48 + 8

M2 = 56 grams

d1 is diffusion of CH4

d2 = diffusion of C4H8

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{56}{16}$ }

$\frac{d_{1}}{d_{2}} = 1.87$

This means CH4 diffuse 1.87 times faster than C4H8

Now, the mathematical part

If velocity of C4H8 = 1 cm/sec , then velocity of CH4 = 1.87 cm/sec

v1 = 1.87 cm/sec

v2 = 1 cm/sec

Let both meet at time "t". If distance travelled by CH4(s1) = x , then remaining(s2) distance (50-x) is travelled by C4H8

(see the attached image)

$time =\frac{distance}{speed}$

since both meet at same time so t = constant.

$\frac{s1}{v1}=\frac{s2}{v2}$

$\frac{x}{1.87}\frac{50-x}{1.00}$

on solving for x we get,

x = 17.42 cm

from the other side the distance is (50 - x)

= 50 - 17.42 = 32.5 cm

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3 years ago

If x is a string, then x = new String("OH"); and x = "OH"; will accomplish the same thing. Group of answer choices True False

Vinvika [58]

Answer:

True is the correct answer to the above question.

Explanation:

If x is a string then it can be assigned by the help of two ways in java:
By the help of constructor:- When we write " x = new String("OH");", then it will create a pass a string "OH" into the constructor. It is because the String is a class in java and x is an object created by the constructor of the String class.
With the help of assigning: The "x= OH", which assigns the value of x which is an object of String class it can also use the constructor to initialize the "OH" string on the class.
The above question states the two scenarios which are defined above. Hence the question statement is true.

5 0

3 years ago

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