Answer:
32.3 dm³
Explanation:
Data given:
no. of molecules of Cl₂ = 8.7 x 10²³
Volume of chlorine gas (Cl₂) = ?
Solution:
First we have to find number of moles
For this formula used
no. of moles = no. of molecules / Avogadros number
no. of moles = 8.7 x 10²³ / 6.022 x 10²³
no. of moles = 1.44 moles
Now we have to find volume of the gas
for this formula used
no. of moles = volume of gas / molar volume
molar volume = 22.4 dm³/mol
Put values in above equation
1.44 moles = volume of Cl₂ gas / 22.4 dm³/mol
rearrange the above equation
volume of Cl₂ gas = 1.44 moles x 22.4 dm³/mol
volume of Cl₂ gas = 32.3 dm³
I think the most appropriate answer is: the solvent being used in the experiment
<span>To correct for any light absorption not originating from the solute you will need to calibrate the tools with a solution that most similar to the sample.
Blank covete or standard solution can be used, but it was not ideal. By using the solvent as calibration, you can remove the reading from the solvent so your result only comes from the sample.
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Answer:
Uh...
Explanation:
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Answer: The concentration of the weak acid in the sample is 0.1224 M
Explanation:
The balanced chemical reaction is :

To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Thus the concentration (in M) of the weak acid in the sample is 0.1224