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Hitman42 [59]
4 years ago
12

How many ions does each of these symbols have, I need answer and my science teacher doesn’t tell us or explain it to us

Chemistry
1 answer:
seropon [69]4 years ago
6 0

Answer: about 14

Explanation:

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PLEASE ANSWER BY 9:00pm PT
astra-53 [7]

Answer:

thanks to all the mortal those who are born must die one day that it cut in cannot be avoided as ripe fruit fall of the tree so it is common to all the mortal those who are born must die one day that it cut

Explanation:

silghjnb bj i bb b nv bv hc U and lamenting produce a few of the tree so much for your time is common to both of us ☺️ to all the said that death of the tree so it cut in cannot be avoided as well as well but the mortal Kombat X the said

7 0
3 years ago
Interpret the following equation for a chemical reaction using the coefficients given:
Liono4ka [1.6K]

Answer:  1 molecule of H_2 reacts with 1 molecule of Cl_2 to give 2 molecules of HCl.

1 mole of H_2 reacts with 1 mole of Cl_2 to give 2 moles of HCl.

Explanation:

The given balanced reaction is:

H_2(g)+Cl_2(g)\rightarrow 2HCl(g)

On the particulate level :

1 molecule of H_2 reacts with 1 molecule of Cl_2 to give 2 molecules of HCl.

On molar level:

1 mole of H_2 reacts with 1 mole of Cl_2 to give 2 moles of HCl.

3 0
3 years ago
Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat of vaporization is 540 cal/g . A canister is
Pani-rosa [81]
<span>294400 cal The heating of the water will have 3 phases 1. Melting of the ice, the temperature will remain constant at 0 degrees C 2. Heating of water to boiling, the temperature will rise 3. Boiling of water, temperature will remain constant at 100 degrees C So, let's see how many cal are needed for each phase. We start with 320 g of ice and 100 g of liquid, both at 0 degrees C. We can ignore the liquid and focus on the ice only. To convert from the solid to the liquid, we need to add the heat of fusion for each gram. So multiply the amount of ice we have by the heat of fusion. 80 cal/g * 320 g = 25600 cal Now we have 320 g of ice that's been melted into water and the 100 g of water we started with, resulting in 320 + 100 = 420 g of water at 0 degrees C. We need to heat that water to 100 degrees C 420 * 100 = 42000 cal Finally, we have 420 g of water at the boiling point. We now need to pump in an additional 540 cal/g to boil it all away. 420 g * 540 cal/g = 226800 cal So the total number of cal used is 25600 cal + 42000 cal + 226800 cal = 294400 cal</span>
6 0
3 years ago
1.Beginning with the new moon, place the phases of the moon in order. Identify each phase.
iVinArrow [24]

Answer:

I cant see the picture but

heeeerrrrreeeee

8 0
3 years ago
How many moles of pentane are in 1.48x1021
vodka [1.7K]

multiply the number of each atom with its molecular mass. (see the periodic table)

5*12 + 12*1 = 72 gram per mole.

Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole

7 0
3 years ago
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