A 1000 N crate is lifted to a height of 3.0 m. How much work is done to lift the crate?

Some hydrogen gas is enclosed within a chamber being held at 200^\ { C} with a volume of 0.025 \rm m^3. The chamber is fitted wi

vlada-n [284]

Answer:

The final volume is $0.039 m^3$

Explanation:

Data:

Initial temperature: $T1=200C$

Final temperature: $T2=200C$

Initial pressure: $P1=1.50 \times10^6 Pa$

Final pressure: $P2=0.950 \times10^6 Pa$

Initial volume: $V1=0.025m^{3}$

Final volume: $V2=?$

Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:

$\frac{PV}{T}=nR$ (1)

With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

Subscript 2 referring to final state and 1 to initial state.

solving for V2:

$V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}=\frac{(1.50 \times10^6)(0.025)(200)}{(200)(0.950 \times10^6)}$

$V_{2}=0.039 m^3$

3 0

3 years ago

Un auto de 1000 kg que lleva una velocidad de 72 km/h se detiene en una distancia de 100 metros cuando se le aplican los frenos.

Flura [38]

Answer:

a) F = 2000 N , B) x = 25 m

Explanation:

a) To solve this exercise we can use the relationship between work and kinetic energy

W = ΔK

The job is

W = -F x

the negative sign is because the force of the brakes is contrary to the movement

as the car stops its final kinetic energy is zero

K = ½ m v²

let's substitute

- F x = 0 - ½ m v²

F = ½ m v² / x

Let's reduce the magnitudes to the SI system

v = 72 km / h (1000m / 1km) (1 h / 3600 s) = 20 m / s

let's calculate

F = ½ 1000 20²/100

F = 2000 N

b) x = ½ mv2 / F

let's slow down to the SI system

v = 36 km / h = 10 m / s

let's calculate

x = ½ 1000 10²/2000

x = 25 m

6 0

3 years ago

A 4.0 kg object will have a weight of approximately 14.8 N on Mars. What is the gravitational field strength on Mars?

zhannawk [14.2K]

Field strength =force/unit mass
= 14.8N/ 4kg = 3.7N/kg

8 0

2 years ago

Read 2 more answers

You whirl a stone in a horizontal circle in such a way that the stone is in uniform circular motion. Which of the following is t

horsena [70]

a. The direction of the stone's velocity changes as it moves around the circle.

b. The magnitude of the stone's velocity does not change.

d. The change in direction of the stone's motion is due to the centripetal force acting on the stone.

Above given are true for the given situation.

Answer: Option A, B and D

Explanation:

Circular motion may be characterized as the moving of an objects along the diameter of the circle or any circular direction. It may be standardized and non-uniform based on whether or not the rate of rotation is unchanged.

The velocity, a vector quantity is constant in a uniform circle motion speed is constant as its direction continues to change. Centripetal force works inward toward the core to counterbalance the centrifugal force from the center moving outward.

4 0

2 years ago

The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?

BigorU [14]

1. Frequency: $7.06\cdot 10^{14} Hz$