Answer:
The final volume is 
Explanation:
<u>Data:</u>
Initial temperature:
Final temperature: 
Initial pressure: 
Final pressure: 
Initial volume:
Final volume: 
Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:
(1)
With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

Subscript 2 referring to final state and 1 to initial state.
solving for V2:


Answer:
a) F = 2000 N , B) x = 25 m
Explanation:
a) To solve this exercise we can use the relationship between work and kinetic energy
W = ΔK
The job is
W = -F x
the negative sign is because the force of the brakes is contrary to the movement
as the car stops its final kinetic energy is zero
K = ½ m v²
let's substitute
- F x = 0 - ½ m v²
F = ½ m v² / x
Let's reduce the magnitudes to the SI system
v = 72 km / h (1000m / 1km) (1 h / 3600 s) = 20 m / s
let's calculate
F = ½ 1000 20²/100
F = 2000 N
b) x = ½ mv2 / F
let's slow down to the SI system
v = 36 km / h = 10 m / s
let's calculate
x = ½ 1000 10²/2000
x = 25 m
Field strength =force/unit mass
= 14.8N/ 4kg = 3.7N/kg
a. The direction of the stone's velocity changes as it moves around the circle.
b. The magnitude of the stone's velocity does not change.
d. The change in direction of the stone's motion is due to the centripetal force acting on the stone.
Above given are true for the given situation.
<u>Answer:</u> Option A, B and D
<u>Explanation:</u>
Circular motion may be characterized as the moving of an objects along the diameter of the circle or any circular direction. It may be standardized and non-uniform based on whether or not the rate of rotation is unchanged.
The velocity, a vector quantity is constant in a uniform circle motion speed is constant as its direction continues to change. Centripetal force works inward toward the core to counterbalance the centrifugal force from the center moving outward.
1. Frequency: 
The frequency of a light wave is given by:

where
is the speed of light
is the wavelength of the wave
In this problem, we have light with wavelength

Substituting into the equation, we find the frequency:

2. Period: 
The period of a wave is equal to the reciprocal of the frequency:

The frequency of this light wave is
(found in the previous exercise), so the period is:
