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3 years ago

What is the relationship between the slope of the position graph of an object and its velocity?

Physics

1 answer:

anastassius [24]3 years ago

8 0

Answer:

Slope of position time is velocity

Explanation:

The position time graph means a relation between the position of the object and the time which is represent on a graph.

The graph line shows that how the position of an object changes with respect to time.

The slope of the position time graph shows the rate of change of position of the object with respect to time.

The rate of change of position with respect to time is called velocity.

thus, the slope of position time graph gives the velocity of the object.

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An astronaut finds herself in a predicament in which she has become untethered from her shuttle. She figures that she could get

Blizzard [7]

In order to solve the problem, it is necessary to apply the concepts related to the conservation of momentum, especially when there is an impact or the throwing of an object.

The equation that defines the linear moment is given by

$mV_i = (m-m_O)V_f - m_OV_O$

where,

m=Total mass

$m_O =$ Mass of Object

$V_i =$ Velocity before throwing

$V_f =$ Final Velocity

$V_O =$ Velocity of Object

Our values are:

$m_1=5.3kgm_2=7.9kg\\m_3=10.5kg\\m_A=75kg\\m_{Total}=m=98.7Kg$

Solving to find the final speed, after throwing the object we have

$V_f=\frac{mV_0+m_TV_O}{m-m_O}$

We have three objects. For each object a launch is made so the final mass (denominator) will begin to be subtracted successively. In addition, during each new launch the initial speed will be given for each object thrown again.

That way during each section the equations should be modified depending on the previous one, let's start:

A) $5.3Kg\rightarrow 15m/s$

$V_{f1}=\frac{mV_0+m_TV_O}{m-m_O}$

$V_{f1}=\frac{(98.7)*0+5.3*15}{98.7-5.3}$

$V_{f1}=0.8511m/s$

B) $7.9Kg\rightarrow 11.2m/s$

$V_{f2}=\frac{mV_{f1}+m_TV_O}{m-m_O}$

$V_{f2}=\frac{(98.7)(0.8511)+(7.9)(11.2)}{98.7-5.3-7.9}$

$V_{f2} = 2.0173m/s$

C) $10.5Kg\rightarrow 7m/s$

$V_{f3}=\frac{mV_{f2}+m_TV_O}{m-m_O}$

$V_{f3}=\frac{(98.7)(2.0173)+(10.5)(7)}{98.7-5.3-7.9-10.5}$

$V_{f3} = 3.63478m/s$

Therefore the final velocity of astronaut is 3.63m/s

7 0

3 years ago

Which of these is not an example of

prohojiy [21]

Answer:

A) The process that give us day and night.

Explanation:

From the answer choices provided the one that is not an example of this is the process that give us day and night. This is because, the day/night cycle occurs as the Earth spins on it's axis. This cause one side of the Earth to be facing the Sun, which is the side that is currently experiencing day time while the other side is experiencing night time. As the Earth spins the cycles repeat. This is not an example of revolving.

5 0

3 years ago

With respect to the earth, object 1 is moving at speed 0.80 c to the right. Object 2 is moving in the same direction at speed 0.

viktelen [127]

Answer:

0.976 c

Explanation:

$v_{1e}$ = velocity of object 1 relative to earth = 0.80 c

$v_{21}$ = velocity of object 2 relative to object 1 = 0.80 c

$v_{2e}$ = velocity of object 2 relative to earth

Velocity of object 2 relative to earth is given as

$v_{2e}= \frac{v_{1e} + v_{21}}{1 + \frac{v_{1e}v_{21}}{c^{2}}}$

$v_{2e}= \frac{0.80 c + 0.80 c}{1 + \frac{(0.80c)(0.80c)}{c^{2}}}$

$v_{2e}$ = 0.976 c

6 0

3 years ago

V (V)

Sergeeva-Olga [200]

Answer:

6755727gvbu7euyeue77377365353663636

Explanation:

ghfjfkjfjfn has a long way is a good relationship is a different person than the difference is that the answer is 8AM is a good relationship with the other 4AM in a certain way is a different type and have different effects and feelings and the difference is the difference is that you can do it for a long period and the same way you know what to smome but you can get to the claire family a lot of times and the difference between the two is that the person you want and you know it would have different opinions on the subject and then use the difference between the two and a half hour and the difference is that the answer is yes but if you're not going anywhere in the past two and your life you can do that with your 6 or an 6th year old girl who is a good things go to

4 0

3 years ago

A 25.0 kg object moving at +15.0 m/s strikes a 15.0 kg

lesya692 [45]

The final velocity of the 15 kg mass is 18.33 m/s.

<h3>Conservation of linear momentum</h3>

The final velocity of the 15 kg mass can be determined by applying the principles of conservation of linear momentum as follows;

$m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\\\\$

Where;

m₁ is the mass of the first object = 25 kg
u₁ is the initial velocity of the first object = 15 m/s
m₂ is the mass of the second object = 15 kg
u₂ is the initial velocity of the second object = -10 m/s
v₁ is the final velocity of the first object = -2 m/s
v₂ is the final velocity of the second object

Thus, the final velocity of the 15 kg mass after the collision is 18.33 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

8 0

2 years ago