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serious [3.7K]
2 years ago
13

A car is traveling at a constant speed on the highway. Its tires have a diameter of 68.0 cm and are rolling without sliding or s

lipping. If the angular speed of the tires is 55.0 rad/s , what is the speed of the car?
Physics
1 answer:
Bad White [126]2 years ago
5 0

Answer:

37.4m/s

Explanation:

since the car doesn't accelerate, we can use the formula v=ωr where v is linear speed, ω is angular speed (rads/second) and r is radius. Substitute values for equation:

v=55*0.68

v=37.40

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Read 2 more answers
How much force (in Newtons) acts on a 1700 kg car going around a
Daniel [21]

Answer:

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Explanation:

Because there is a redius do this question is talking about the acceleration force which= mv^2/r

so a=15^2/80=2.8125 m^2/s

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2 years ago
A block with mass m =6.9 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.24 m.
Burka [1]
U need to set up n solve the general eqn for simple harmonic motion:
x" = -(k/m)x

solution is x(t) = (x0)*cos(wt) + (v0/w)*sin(wt)
where w=sqrt(k/m), x0 is x-position at t=0 and v0 is vel at t=0
u already calculated f in Q.2 and w = 2*pi*f
x0 is 0 as it starts at eqm
v0 is given at 5.1

so u have x(t)

vel is given by x'(t) = (x0)*(-w)*sin(wt) + (v0/w)*w*cos(wt)

substitute t=0.32, x0=0, v0=5.1 n w in the above, u can solve for v at t=0.32.

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3 years ago
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ANEK [815]
24km/hour=(20/3)m/s
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6 0
2 years ago
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