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DiKsa [7]
3 years ago
9

How is drip irrigation better than canal irrigation?Explain as well

Chemistry
2 answers:
Lilit [14]3 years ago
7 0
In canal irrigation its not easy to control flow of water. ... in drip irrigation method pipe system is applied in fields and pipes have holes. these holes are directed perpendicularly to plants root.
Fudgin [204]3 years ago
7 0

unlike a sprinkler system that will Splash water all over the foliage of your plants a drip irrigation system will apply to water the plants where can easily be taken in by their roots

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A student makes a cross-section clay model to represent the internal structure of a volcano that leads to the formation of two r
Murrr4er [49]

CAnswer:

Explanation:

6 0
3 years ago
Why is the symbol for the element sulfur and the formula for a molecule of sulfur differ
lukranit [14]

Answer:

Sulfur (S) is an element while the formula for this element is not just sulfur (e.g. H2S, SO2)

Explanation:

5 0
3 years ago
12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution. What was the molarity of the HCl
frozen [14]

The molarity of the HCl is 1 M when 12.0 of .500 M NaOH neutralized 6.0 ml of HCl solution.

Explanation:

Data given:

molarity of the base NaOH, Mbase =0. 5 M

volume of the base NaOH, Vbase = 12 ml

volume of the acid, Vacid = 6 ml

molarity of the acid, Macid = ?

The titration formula for acid and base is given as:

Mbase Vbase = Macid Vacid

Macid =\frac{0. 5 X 12}{6}

Macid = 1 M

we can see that 1 M solution of HCl was used to neutralize the basic solution of NaOH. The volume of NaOH is 12 ml and volume of HCl used is 6ml.

8 0
3 years ago
cyclopropane is a commonly used anesthetic. If a 2.00 L flask contains 3.11 g of cyclopropane gas at 684 mmHg pressure and 23.0
jeka94

Answer:

42.0g/mol

Explanation:

The steps for this question is to use the ideal gas law, and then use n=m/M to find molar mass.

PV = nRT

n= PV/RT

Change 23 degrees to 296.15 K and 684mmHg to kpa

n = (91.1925kpa)(2.00L)/(8.314Lkpa/mol K)(296.15K)

n= 0.074mol

n = m/M

M = m/n

M = 41.98489g/mol

8 0
2 years ago
What is one disadvantage of wind and hydroelectric power?OA. Their supplies are limited and only last a few years in a singlocat
Goshia [24]

Answer:

C

Explanation:

Here, we want to select a disadvantage of the power sources

The two listed are examples of renewable power sources with no level of pollution

However, in the case of wind, a wind turbine is needed and could only work in places where the wind is prevalent enough throughout the year. Likewise, hydroelectric power, can only work where we have a flowing water source

Thus, there is a bane of geographic and climatic restrictions serving as a disadvantage

4 0
1 year ago
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