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Alenkasestr [34]
2 years ago
12

If a deck of cards is 7/10 of an inch tall, how tall is the package of 6 decks of cards?

Mathematics
1 answer:
kaheart [24]2 years ago
5 0
If one is 7/10
Then 6 will be 7/10 * 6 or 42/10 inches
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Given that r= 2p2/q-3 ; rearrange the formula to make q the subject of the formula.
Vesnalui [34]

Step-by-step explanation:

The given expression is:

r=\dfrac{2p^2}{q-3}

We need to solve it to make q the subject of the formula.

Cross multiplying both sides,

rq-3r=2p^2

Adding 3r to both sides,

rq-3r+3r=2p^2+3r\\\\rq=2p^2+3r

Now, dividing both sides by r,

q=\dfrac{2p^2+3r}{r}

Hence, this is the required solution.

7 0
3 years ago
Which of the following is an example of an open equation? 5x + 7 = 12 , 12 + (-8) = 4 , 25 = 5 (5) , 8 + 0 =8
spayn [35]

An open equation is an equation that contain one or more unknow variables.

And that/those variable(s) can be found by solving the equation that make the equation true.

A variable is an English alphabet.

For example, a,b, x, y,z etc.

A variable represents a unknow value for a particular quantity.

In the given options 5x + 7 = 12 , 12 + (-8) = 4 , 25 = 5 (5) , 8 + 0 =8 .

In first option, we have unknow variable x is there.

But in all other options we don't value any variable.

Therefore, all other options can't be open equation.

So, final answer is 5x + 7 = 12 is the only open equation in given options.

7 0
3 years ago
Which ordered pairs make both inequalities true? Select two options. y < 5x + 2 y > One-halfx + 1 On a coordinate plane, 2
Verdich [7]

Answer:

(1, 2)

(2,2)

Step-by-step explanation:

The inequality Given :

y < 5x + 2

y ≥ One-halfx + 1

We can use the values in the options to see which satisfies the inequality :

(-1, 3) ; X = - 1, y = 3

3 < 5(-1) + 2 ; 3 < - 4 (not true)

(0, 2) ; X = 0 ; y = 2

2 < 5(0) + 2 ; 2 < 2 (nor true)

2 > 1/2(0) + 1

2 > 1 (true)

Using (1, 2).; x = 1 ; y = 2

2 < 5(1) + 2 ; 2 < 7 (true)

2 > 1/2(1) + 1 ; 2 > 1.5 (true)

Using (2, 2)

y < 5x + 2

2 < 10 + 2 ; 2 < 12 (true)

y > 1/2x + 1

2 > 1/2(2) + 1 ; 2

8 0
3 years ago
PLS HELP ASAP!!!!!!!!!!!!!!
Likurg_2 [28]
The IQR is the difference between Q3 and Q1.
First we need to get the data from the stem and leaf plot:
10, 23, 23, 28,]   [33, 45, 80, 90
Since there are 8 data items Q1 would be the median of the lower half (4 items), both are 23 so Q1 is 23.
Q3 is the median of the upper half, since the middle numbers are not the same we need to average 45 and 80. (45 + 80)/2 = 62.5 so Q3 = 62.5
IQR = 62.5 - 23 = 39.5

7 0
3 years ago
Let X denote the number of bars of service on your cell phone whenever you are at an intersection with the following probabiliti
lorasvet [3.4K]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: number of bars of service on your cell phone.

The posible values of this variable are {0, 1, 2, 3, 4, 5}

a. F(X) is the cummulative distribution function P(X≤x₀) you can calculate it by adding all the point probabilities for each value:

X: 0; 1; 2; 3; 4; 5

P(X): 0.15; 0.25; 0.25; 0.15; 0.1; 0.1

F(X): 0.15; 0.4; 0.65; 0.8; 0.9; 1

The maximum cumulative probability of any F(X) is 1, knowing this, you can calculate the probability of X=5 as: 1 - F(4)= 1 - 0.9= 0.1

b.

The mean of the sample is:

E(X)= ∑Xi*Pi= (0*0.15)+(1*0.25)+(2*0.25)+(3*0.15)+(4*0.1)+(5*0.1)

E(X)= 2.1

V(X)= E(X²)-(E(X))²

V(X)= ∑Xi²*Pi- (∑Xi*Pi)²= 6.7- (2.1)²= 2.29

∑Xi²*Pi= (0²*0.15)+(1²*0.25)+(2²*0.25)+(3²*0.15)+(4²*0.1)+(5²*0.1)= 6.7

c.

P(X<2)

You can read this expression as the probability of having less than 2 bars of service. This means you can have either one or zero service bars, you can rewrite it as:

P(X<2)= P(X≤1)= F(1)= 0.4

d.

P(X≤3.5)

This expression means "the probability of having at most (or less or equal to) 3.5 service bars", this variable doesn't have the value 3.5 in its definition range so you have to look for the accumulated probability until the lesser whole number. This expression includes the probabilities of X=0, X=1, X=2, and X=3, you can express it as the accumulated probability until 3, F(3):

P(X≤3.5)= P(X≤3)= F(3)= 0.80

I hope it helps!

5 0
3 years ago
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