If a deck of cards is 7/10 of an inch tall, how tall is the package of 6 decks of cards?

What is the quotient of 4 2/3 divided by 4 1/5 :fraction

Ostrovityanka [42]

Write the two fractions as improper fractions
4 2/3 is 14/3
<span>4 1/5</span> is 21/5
rewrite
14/3 <span>÷ 21/5
since it is pretty complicated to divide two fractions,
you change it to multiplication
keep the first fraction, change the division sign to multiplication, then flip the second fraction
(you can remember KEEP, CHANGE, FLIP whenever dealing with division of fractions :) )
14/3 * 5/21
multiply across
(14 * 5) / ( 3 * 21)
</span>70/ 63
simplify to 10/9
this can be written as 1 1/9

Hope this helps

8 0

3 years ago

Read 2 more answers

Which of the following is an infinite series?

Brut [27]

<h3>Answer: Choice C) 2 - 6 + 18 - 54 + ...</h3>

Explanation:

The three dots or ellipses indicate the pattern goes on forever to infinity. So the answer is between choices A and C based on this alone. Choice A is a sequence while choice C is a series. A sequence is simply a list of values often in some kind of mathematical pattern. A series is where you add values from a sequence together. This distinction rules out choice A and makes choice C the answer.

Note: choice C is a geometric series with first term 2 and common ratio -3. The infinite series diverges because r = -3 is outside the range -1 < r < 1.

4 0

3 years ago

HeLp pLeAsE

zhenek [66]

Answer:

29.655

Step-by-step explanation:

Adding a negative number to a positive number is easy.

Subtract -3.095 from 32.750 which equals 29.655.

8 0

3 years ago

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-3s is greater than or less than 33

astraxan [27]

The answer for this question is less than.

4 0

3 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago