We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90
Since the truck is 8 feet long then the longest log able to fit in the truck should be 8 feet as well. However talking reality, we might want to shorten it to make it fit better. Hope this helps!
<h2>
Answer:</h2>
<em><u>The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>
<h2>
Step-by-step explanation:</h2>
In the question,
The maximum height of the vehicle which is capable of passing under the bridge is 12 feet and 5 inches.
So,
Now we know that,
1 feet = 12 inches
So,
12 feet = 12 x 12 = 144 inches
So,
Total height of the vehicle which is permissible to pass under the bridge is,
12 feet 5 inches = 144 + 5 = 149 inches
Also,
Height of the truck = 162 inches
Therefore, we can see that the permissible height is smaller than the height of the vehicle.
Height of vehicle which is more than permissible height is by,
162 - 149 = 13 inches
<em><u>Therefore, the truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>
Answer:
Step-by-step explanation:
Rewrite this as
Knowing that i-squared = -1:
Both i-squared and 100 are perfect squares, so this simplifies to
±10i
