Answer:
Percentage yield of MgCl₂ = 83.4%
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
Mg + 2HCl —> MgCl₂ + H₂
Next we shall determine the mass of of Mg that reacted and the mass of MgCl₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of Mg = 24 g/mol
Mass of Mg from the balanced equation = 1 × 24 = 24 g
Molar mass of MgCl₂ = 24 + (35.5×2)
= 24 + 71
= 95 g/mol
Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g
SUMMARY:
From the balanced equation above,
24 g of Mg reacted to produce 95 g of MgCl₂.
Next, we shall determine the theoretical yield of MgCl₂. This can be obtained as follow:
From the balanced equation above,
24 g of Mg reacted to produce 95 g of MgCl₂.
Therefore, 100 g of Mg will react to produce = (100 × 95)/24 = 395.83 g of MgCl₂.
Thus, the theoretical yield of MgCl₂ is 395.83 g
Finally, we shall determine the percentage yield of MgCl₂. This can be obtained as follow:
Actual yield of MgCl₂ = 330 g
Theoretical yield of MgCl₂ = 395.83 g
Percentage yield of MgCl₂ =?
Percentage yield = Actual yield /Theoretical yield × 100
Percentage yield = 330 / 395.83 × 100
Percentage yield of MgCl₂ = 83.4%
