Answer:
C) 0.24 M
Explanation:
The given chemical reaction is presented as follows;
H₂SO₄(aq) + 2 KOH(aq) → K₂SO₄(aq) + 2 H₂O(l)
The titration experiment results are;
Volume of H₂SO₄(aq) used = 12.0 mL
Volume of KOH (aq) used = 36.0 mL
Concentration of KOH (aq) = 0.16 M
The number of moles of KOH present, n = 0.16 M × 36/1000 = 0.00576 moles
From the given reaction, 1 mole of H₂SO₄ reacts with 2 moles of KOH to give 1 mole of K₂SO₄ and 2 moles of H₂O
Therefore, 0.00576 moles of KOH reacts with (1/2) × 0.00576 moles = 0.00288 moles of H₂SO₄
Therefore, for the reaction;
The number of moles of H₂SO₄ in 12.0 mL of H₂SO₄ = 0.00288 moles
The concentration of the H₂SO₄ = 0.00288 M/(12.0 mL) = 0.24 M
The concentration of H₂SO₄ in the reaction = 0.24 M.
A chemical formula can tell one the consisting atoms, the types of atoms and which they belong.Also through mole ratios, the number of atoms contained in a compound can also be identified through the chemical formula. In this problem, the answer is a. True.
Answer:
is the rate constant for this reaction.
It will take 
to concentration to reach 12.5% of its original value.
Explanation:
A decomposition reaction follows first order kinetics:
Half life of the reaction = 
Rate constant of the reaction = k
For first order reaction, half life and rate constant are linked with an expression :
is the rate constant for this reaction.
Initial concentration of reactant =![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= x
Final concentration of reactant after time t =![[A]](https://tex.z-dn.net/?f=%5BA%5D)
= 12.5% of x = 0.125x
The integrated law of first order reaction :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
t = 1,734.31 years =
It will take to concentration to reach 12.5% of its original value.
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:
Thus, given the values of the enthalpies of formation on the attached file, we obtain:
Best regards!
Answer: A:5 B:2 C:15 D:8 E:O
Explanation:
just checked on edg
