Question

What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?

Answer 1

Answer: A volume of 500 mL water is required to prepare 0.1 M $H_{3}PO_{4}$ from 100 ml of 0.5 M solution.

Explanation:

Given: $M_{1}$ = 0.1 M,    $V_{1}$ = ?

$M_{2}$ = 0.5 M,       $V_{2}$ = 100 mL

Formula used to calculate the volume of water is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL$

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M $H_{3}PO_{4}$ from 100 ml of 0.5 M solution.