Given info:
Compound Interest = Rs.1290
Rate of Interest = 15% p.a
Time = 2 years
<h3>Formula we have to know:-</h3>
<u>Where</u>
C.I = Compound Interest
P = Principle
R = Rate of Interest
N = Time
Here
C.I = Rs.1290
R = 15%
N = 2 years
Principle = ?
Now,Calculating the sum (Principle) borrowed by Rachna
![\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%20%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7BC.I%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%281%20%20%2B%20%5Cdfrac%7BR%7D%7B100%7D%20%5Cbigg%29%5E%7Bn%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
Substituting the given values
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%281%20%20%2B%20%5Cdfrac%7B15%7D%7B100%7D%20%5Cbigg%29%5E%7B2%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B%281%20%5Ctimes%20100%29%20%2B%2015%7D%7B100%7D%20%5Cbigg%29%5E%7B2%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B115%7D%7B100%7D%20%5Cbigg%29%5E%7B2%7D%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B115%7D%7B100%7D%20%5Ctimes%20%5Cdfrac%7B115%7D%7B100%7D%20%20%5Cbigg%29%20%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%5Cdfrac%7B13225%7D%7B10000%7D%20%5Cbigg%29%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%20%5Ccancel%7B%5Cdfrac%7B13225%7D%7B10000%7D%7D%20%5Cbigg%29%20-%201%20%5CBigg%5D%7D%7D%7D)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}](https://tex.z-dn.net/?f=%5Cquad%7B%3A%20%5Cimplies%7B%5Csf%7B1290%20%3D%20%20%5CBigg%5BP%20%20%5Cbigg%28%7B1.3225%20-%201%7D%20%5Cbigg%29%20%5CBigg%5D%7D%7D%7D)
<u>Hence,</u>
The sum (Principle) is Rs.4000.
Answer:
18
Step-by-step explanation:
I did my method that I was taught but if you do (-5) - (-2), you get 3. So you subtract 39 by the -21 to get 18.
Answer:
Powers are : 4, 16 64 and 256
and this question type of question was answered from another brainly user as well lol
Answer:
Present Perfect Tense Examples
Has lived: She has lived here all her life.
Have written: They have written three letters already.
Have worked: I have worked here since I graduated school.
Has done: He has finished his homework.
Have been: We have been to Canada.
Has forgotten: She has forgotten her folder.
Step-by-step explanation:
Answer:
c=A/2n
Step-by-step explanation:
A=2nc
c=A/2n
