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Veseljchak [2.6K]
3 years ago
5

On a map, Melbourne, Australia, is 22 centimeters from Sydney, Australia. The actual distance is 880 kilometers. If Canberra, Au

stralia, is 286 kilometers from Sydney, how far apart will they appear on the map, to the nearest centimeter? 3 centimeters 7 centimeters 13 centimeters 68 centimeters
Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0
7 centimeters because you have to find how many kilometers are in each kilometer and that is 40 so then you divide 286 by 49 which is 7.15 then you round
IgorLugansk [536]3 years ago
7 0

Answer: 7 cm

Step-by-step explanation:

In the Map,

The distance of Australia from Sydney = 22 cm,

But, the actual distance of Australia from Sydney = 880 km,

Thus, In the map the scale is,

880 km = 22 cm

\implies 1\text{ km}=\frac{22}{880}= \frac{1}{40}\text{ cm}

\implies 286\text{ km}= 286\times \frac{1}{40}=\frac{286}{40}=7.15\text{ cm}\approx 7 \text{ cm}

Since, the actual Canberra from Sydney in the map = 286 km

Thus, the distance of Canberra from Sydney in the map = 7 cm (approx)  

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Answer:

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2 years ago
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If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

JL = 2 * 13

JL = 26

Solving (c): KL

To solve for KL, we consider triangle KNL where:

\angle KNL = 90

and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

KL^2 = 394

KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

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3 years ago
How do you find the scale factor of two triangles, 0.3 and 2.4?
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Divide the larger one by the smaller one. 2.4 divided by 0.3 gives you 8. That means the scale factor is 8, or the larger triangle is 8 times larger than the smaller. We can prove this by multiplying 0.3 by 8 and getting 2.4
8 0
3 years ago
Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did
svetoff [14.1K]
I added a screenshot with the complete question

<u><em>Answer:</em></u>
Total miles = 2.5 miles

<u><em>Explanation:</em></u>
<u>1- While walking:</u>
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked \frac{20}{60} =  \frac{1}{3} of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while walking:</u>
Distance = 3 * \frac{1}{3} = 1 mile

<u>2- While running:</u>
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran \frac{15}{60} =  \frac{1}{4} of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while running:</u>
Distance = 6 * \frac{1}{4} = 1.5 miles

<u>3- getting the total mileage:</u>
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

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Do you see the pattern? <em>3^{n} where n is the number of hours</em>

Answer: 3³, 3^{n}

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3 years ago
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